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marissa [1.9K]
3 years ago
15

which equation listed matches the following word equation? when lithium hydroxide pellets are added to a solution of sulfuric ac

id, lithium sulfate and water are formed.
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
6 0
LiOH + H2SO4 <span>→ Li2SO4 + H2O

Balance the equation:

Reactants:
Li = 1 • 2
O = 1 • 2 + 4
H = 1 • 2+ 2
S = 1

Products:
Li = 2
O = 4 + 1 • 2
H = 2 • 2
S = 1

Balanced Equation:

</span>2LiOH + H2SO4 → Li2SO4 + 2H2O
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Using your knowledge of chemistry and the information in Reference Table H, which statement concerning propanone and water at 50
stiv31 [10]
The answer is (2) higher vapor pressure and weaker intermolecular forces. Propanone has a lower boiling point, so it is more volatile than water. Propanone's vapor pressure is, therefore, higher than that of water at 50 degrees Celsius. Propanone is more volatile due to the fact that the intermolecular forces that hold its molecuels together are not as strong as those that hold together molecules of water. Since the IMFs are weaker, it takes less thermal energy to break individual molecules free of each other.
3 0
3 years ago
How many hydrogen atoms are present in .46 moles of NH3
mixas84 [53]

Answer:

2.78 x 10²³

Explanation:

1 mole contains 6.02 x 10²³ hydrogen atoms => 0.46 mole contains 0.46(6.02 x 10²³) hydrogen atoms or 2.78 x 10²³ atoms.

Caution => When to use H vs H₂ => This problem is specific for 'hydrogen atoms' but some may simply say hydrogen. In such cases use H₂ or 'molecular hydrogen' is the focus. it's a matter of semantics, H vs H₂.    

3 0
3 years ago
You are given a solution of HCOOH (formic acid) with an approximate concentration of 0.20 M and you will titrate this with a 0.1
jeka57 [31]

Answer:

\boxed{\text{36 mL}}

Explanation:

1. Write the balanced chemical equation.

\rm HCOOH + NaOH $ \longrightarrow$ HCOONa + H$_{2}$O

2. Calculate the moles of HCOOH

\text{Moles of HCOOH} =\text{20.00 mL HCOOH } \times \dfrac{\text{0.20 mmol HCOOHl}}{\text{1 mL HCOOH}} = \text{4.00 mmol HCOOH}

3. Calculate the moles of NaOH.

\text{Moles of NaOH = 4.00 mmol HCOOH } \times \dfrac{\text{1 mmol NaOH} }{\text{1 mmol HCOOH}} = \text{4.00 mmol NaOH}

4. Calculate the volume of NaOH

c = \text{4.00 mmol NaOH } \times \dfrac{\text{1 mL NaOH }}{\text{0.1105 mmol NaOH }} = \textbf{36 mL NaOH }\\\\\text{The titration will require }\boxed{\textbf{36 mL of NaOH}}

3 0
3 years ago
Given the value of the equilibrium constant (Kc) for the equation (a), calculate the equilibrium constant for equation (b)
matrenka [14]

Answer: The value of equilibrium constant for new reaction is 1.92\times 10^{-25}

Explanation:

The given chemical equation follows:

O_2(g)\rightarrow \frac{2}{3}O_3(g)+\frac{1}{2}O_2(g)  

The equilibrium constant for the above equation is 5.77\times 10^{-9}

We need to calculate the equilibrium constant for the equation of 3 times of the above chemical equation, which is:

3O_2(g)\rightarrow 2O_3(g)

The equilibrium constant for this reaction will be the cube of the initial reaction.

If the equation is multiplied by a factor of '3', the equilibrium constant of the new reaction will be the cube of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

K_{eq}'=(5.77\times 10^{-9})^3=1.92\times 10^{-25}

Hence, the value of equilibrium constant for new reaction is 1.92\times 10^{-25}

5 0
3 years ago
Which of the following statements best predicts the pH value of H2CO3 and KOH?
worty [1.4K]

Answer:

The 2nd one

Explanation:

ITS THE RIGHT ANSWER

4 0
3 years ago
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