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marissa [1.9K]
3 years ago
15

which equation listed matches the following word equation? when lithium hydroxide pellets are added to a solution of sulfuric ac

id, lithium sulfate and water are formed.
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
6 0
LiOH + H2SO4 <span>→ Li2SO4 + H2O

Balance the equation:

Reactants:
Li = 1 • 2
O = 1 • 2 + 4
H = 1 • 2+ 2
S = 1

Products:
Li = 2
O = 4 + 1 • 2
H = 2 • 2
S = 1

Balanced Equation:

</span>2LiOH + H2SO4 → Li2SO4 + 2H2O
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Stable nuclei with low atomic numbers, up to 20, have a neutron to proton ratio of approximately ________.
Pie
1 to 1. Most small atoms have the same number of protons and neutrons
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To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w
Elis [28]

<u>Answer:</u> The number of moles of weak acid is 4.24\times 10^{-3} moles.

<u>Explanation:</u>

To calculate the moles of KOH, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}

We are given:

Volume of solution = 43.81 mL = 0.04381 L      (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol

The chemical reaction of weak monoprotic acid and KOH follows the equation:

HA+KOH\rightarrow KA+H_2O

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, 4.24\times 10^{-3}mol of KOH will react with = \frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol of weak monoprotic acid.

Hence, the number of moles of weak acid is 4.24\times 10^{-3} moles.

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Active or reflective listening is the single most useful and important listening skill. In active listening, we also are genuinely interested in understanding what the other person is thinking, feeling, wanting, or what the message means, and we are active in checking out our understanding before we respond with our own new message. We restate or paraphrase our understanding of their message and reflect it back to the sender for verification. This verification or feedback process is what distinguishes active listening and makes it effective.

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3 0
3 years ago
A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
Mandarinka [93]
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as

pH = pKa + log [A]/[HA] 

 where pKa = - log [Ka]
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[HA] is the concentration of the acid

Given:
Ka = 1.8x10^-5
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NaC2H3O2 = 0.1 mol

Solution:
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pH = 4.74 + log (.115/0.085)
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