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faust18 [17]
3 years ago
14

Driving to work one morning, you get a flat tire. When using the car jack, you apply 120 N of force to the jack and the jack in

turn applies 2000 N of force to lift the car up. What is the mechanical advantage of the jack? (Chapter 4 – Page 111)
Chemistry
1 answer:
svetlana [45]3 years ago
7 0

16.7

Explanation:

Given parameters:

Force applied to Jack = 120N

Force produced by Jack = 2000N

Unknown:

Mechanical advantage of jack = ?

Solution:

Mechanical advantage is the ratio of force produced by the device and the force applied on it.

It is used to access the performance of a machine.

M.A = \frac{force output}{force input}

Now input the parameters;

  M.A = \frac{2000}{120}

 M.A = 16.7

learn more:

Force brainly.com/question/10470406

#learnwithbrainly

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Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:
posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of HNO_3 = \frac{15.5g}{63g/mol\times 9.5L}=0.026M

Equilibrium concentration of NO = \frac{16.6g}{30g/mol\times 9.5L}=0.058M

Equilibrium concentration of NO_2 = \frac{22.5g}{46g/mol\times 9.5L}=0.051M

Equilibrium concentration of H_2O = \frac{189.0g}{18g/mol\times 9.5L}=1.10M

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_c  

For the given chemical reaction:

2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)

The expression for K_c is written as:

K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}

K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}

K_c=3.72

Thus  the value of the equilibrium constant Kc for this reaction is 3.72

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