Answer:
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
Explanation:
The substance having highest positive reduction 
potential will always get reduced and will undergo reduction reaction.
Reduction : cathode
..[1]
Oxidation: anode
..[2]
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the 
of the reaction, we use the equation:
The overall reaction will be:
2 × [1] + 3 × [2] :
Electrons on both sides will get cancelled :
Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.
The heat of solution is -51.8 kJ/mol
<h3>What is the heat of solution?</h3>
We know that in a calorimeter, there is no loss or gain of energy. It is a good example of a closed system.
Number of moles of KOH = 11.9-g/56 g/mol = 0.21 moles
Temperature rise = 26.0 ∘c
Mass of the water = 100.0 grams
Heat capacity = 4.184 j/g⋅°c
Then;
ΔH = mcθ
ΔH = 100g * 4.184 j/g⋅°c * 26.0 ∘c = 10.88 kJ
Heat of solution = -(10.88 kJ/ 0.21 moles) = -51.8 kJ/mol
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Answer:
0.1 M
<h3>
Explanation:</h3>
- Molarity refers to the concentration of a solution in moles per liter.
- It is calculated by dividing the number of moles of solute by the volume of solvent;
- Molarity = Moles of the solute ÷ Volume of the solvent
<u>In this case, we are given;</u>
- Number of moles of the solute, NH₄Cl as 0.42 moles
- Volume of the solvent, water as 4200 mL or 4.2 L
Therefore;
Molarity = 0.42 moles ÷ 4.2 L
= 0.1 mol/L or 0.1 M
Thus, the molarity of the solution will be 0.1 M
We can describe a positive energetic process as any process which increases the internal energy of the system.
A positive energetic reaction or process is often referred to as being Endothermic. This means that the system which is performing the process absorbs energy. Some examples include:
- Boiling an Egg
- Roasting food over a fire (the food is the reference system)
etc
Therefore, we can confirm that a positive energetic process is one in which the system in question absorbs energy, thus increasing its internal energy.
<em>Since I could not locate the options online, I have provided a general explanation of the concept coupled with a few examples.</em>
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