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faust18 [17]
4 years ago
14

Driving to work one morning, you get a flat tire. When using the car jack, you apply 120 N of force to the jack and the jack in

turn applies 2000 N of force to lift the car up. What is the mechanical advantage of the jack? (Chapter 4 – Page 111)
Chemistry
1 answer:
svetlana [45]4 years ago
7 0

16.7

Explanation:

Given parameters:

Force applied to Jack = 120N

Force produced by Jack = 2000N

Unknown:

Mechanical advantage of jack = ?

Solution:

Mechanical advantage is the ratio of force produced by the device and the force applied on it.

It is used to access the performance of a machine.

M.A = \frac{force output}{force input}

Now input the parameters;

  M.A = \frac{2000}{120}

 M.A = 16.7

learn more:

Force brainly.com/question/10470406

#learnwithbrainly

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Percentage Weight-in-volume is defined as the <em><u>number of grams of a solute in a 100 ml (milliliters) solution.</u></em>

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The <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.

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a% of a glucose solution =<u> a grams of glucose in a 100 mL solution</u>

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Water and carbon dioxide are waste products released as a direct result of​
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How many atoms are in 10.1 g Ne
LekaFEV [45]

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Given] 10.1 g Ne

[Solve] atoms Ne

<u>Step 2: Identify Conversions</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})
  2. [DA] Divide/Multiply [Cancel out units]:                                                          \displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

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