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lara [203]
2 years ago
7

Light of the same wavelength passes through two diffraction gratings. One grating has 4000 lines/cm, and the other one has 6000

lines/cm. Which grating will spread the light through a larger angle in the first-order pattern
Physics
1 answer:
babunello [35]2 years ago
7 0

Answer:

6000 lines/cm

Explanation:

From the question we are told that:

Grating 1=4000 lines/cm

Grating 2=6000 lines/cm

Generally The Spread of fringes is Larger when the Grating are closer to each other

Therefore

Grating 2 will spread the the light through a larger angle in the first-order pattern because its the closest with 6000 lines/cm

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A weight lifter applies an upward force of 1100 N while lowering a dumbbell
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Answer:

A

Explanation:

work = force \times distance

work = 1100 \times 0.5

= 550 \: j

hope it helped a lot

pls mark brainliest with due respect .

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2 years ago
1. A brick and a peanut are dropped of the roof of a house at the same time, which
iris [78.8K]

Answer:

It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give

Explanation:

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When it reacts with another element, an oxygen atom gains two electrons.
luda_lava [24]

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A

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An ion with a negative charge

3 0
3 years ago
Read 2 more answers
A bird sits on a high-voltage power line with its feet 3.87 cm apart. The wire is made from aluminum, is 2.11 cm in diameter, an
Svetlanka [38]

Answer:

ΔV=0.484mV

Explanation:

The potential difference across the end of conductor that obeys Ohms law:

ΔV=IR

Where I is current

R is resistance

The resistance of a cylindrical conductor is related to its resistivity p,Length L and cross section area A

R=(pL)/A

Given data

Length L=3.87 cm =0.0387m

Diameter d=2.11 cm =0.0211 m

Current I=165 A

Resistivity of aluminum p=2.65×10⁻⁸ ohms

So

ΔV=IR

=I(\frac{pL}{A})\\ =I(\frac{pL}{\pi r^{2} } )\\=I(\frac{pL}{\pi (d/2)^{2} } )\\=165A((\frac{(2.65*10^{-8})(0.0387m)}{\pi (0.0211m/2)^{2} } ))\\=4.84*10^{-4}V

ΔV=0.484mV  

3 0
2 years ago
A student standing on a knoll throws a snowball horizontally 4.5 meters above the level ground toward a smokestack 15 meters awa
Elan Coil [88]

Answer:

2.4 m

Explanation:

Consider the motion along the vertical direction

y_{o} = initial position of ball above the ground = 4.5 m

t = time taken by the ball to hit the smokestack = 0.65 s

v_{oy} = initial velocity of the ball along vertical direction

a_{y} = acceleration due to gravity = - 9.8 m/s²

y = position of ball at the time of hitting the smokestack

Using the kinematics equation

y = y_{o} + v_{oy} t + (0.5) a_{y} t^{2}

inserting the above values

y = 4.5 + (0) (0.65) + (0.5) (- 9.8) (0.65)^{2} \\y = 2.4 m

6 0
3 years ago
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