What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?
        
             
        
        
        
Answer: 8Ω
Explanation:
Since there are two resistors of 4Ω
connected in series, the total resistance (Rtotal) of the circuit is the sum of each resistance.
i.e Rtotal = R1 + R2
R1 = 4Ω 
R2 = 4Ω 
Rtotal = ?
Rtotal = 4Ω + 4Ω
Rtotal = 8Ω 
Thus, the total resistance of the circuit is 8Ω