Question

BASEBALL IN SPACE baseball in space You are observing a baseball in space, with mass m = 0.145 kg. It is moving past your spacecraft with speed v = 22.9 m/sec, to the north. Your Acme Tractor Beam can exert 1.3 Newtons of pull force on that baseball. CALCULATE: How long will it take your Acme Tractor Beam to slow down the baseball to a stop? Enter the numeric part of your answer, to the nearest hundredth of a second, i.e., 0.01 sec. E.g., if your answer is 60.5329 sec, then type in 60.53 in the answer box.

Answer 1

Answer:

It takes 2.55 sec

Explanation:

First we need to find the aceleration with this equation:

F = m*a

$a = \frac{F}{m}$

Where:   F = 1.3 Newtons

              m = 0.145 kg

Then      $a = \frac{1.3 Newtons}{0.145 kg}$

              $a = 8.9655 m/sec^{2}$

Now we are ready to calculate the time with the next equation:

$V_{f} = V_{o} + a*t$

$V_{f} - V_{o} = a*t$

$t = \frac{V_{f} - V_{o}}{a}$

Where:   $V_{o} = 22.9 m/sec$   (at the beginning)

              $V_{f} = 0 m/sec$   (at the end because it stops)

We must use $a = - 8.9655 m/sec^{2}$   because in this case speed is decreasing

Finally:   $t = \frac{0 m/sec - 22.9 m/sec}{- 8.9655 m/sec^{2} }$

              t = 2.55 sec