Answer:
The new period will be √6 *T
Explanation:
period ,T=2π√(L/g) ................equation 1
where T is the period on earth
gravitational acceleration on the moon is g/6
T1 = 2π√[L/(g/6)]
T1=2π√(6L/g) ...............equation 2
divide equation 2 by 1
T1/T =2π√(6L/g)÷2π√(L/g)
T1/T =√(6L/L)
T1/T =√6
T1 = √6 *T
Answer:
a) 
b) 
c) 
Explanation:
Given masses:
Velocity of mass 1, 
Velocity of mass 2, 
a)
Initial momentum:
b)
magnitude of initial momentum:
From the conservation of momentum:
is the magnitude of final velocity.
Direction of final velocity will be in the direction of momentum:
c)
Vertical component of final velocity:
<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
In order to make any headway with this one, it might help
to know how many joules there are in one BTU, ya reckon ?
I went and looked it up on line, you're welcome.
1 BTU = 1055.06 joules .
So if you happen to have 1,152 BTU of energy,
there are 1055.06 joules in each one of them,
and the total is
(1,152 BTU) x (1,055.06 joule/BTU)
= 1,215,429.12 joules .
Scanning the choices for anything close, we notice that choice-'b'
is only about 0.006% less than my answer. So that must be the one
they're fishing for, and they must have used 1055-even for their
conversion factor.
I think it would be C: Sometimes true and sometimes false. It varies.
Hope this helped, have a great day! :D
