All categories

3 years ago

HURRY WILL GIVE BRAINLIEST

Physics

1 answer:

andrey2020 [161]3 years ago

8 0

The amount of energy needed to melt the ice is 1670 J

Explanation:

The amount of thermal energy needed to completely melt a certain amount of solid substance (already at melting point) is given by

$Q=m\lambda_f$

where

m is the amount of the substance

$\lambda_f$ is the specific latent heat of fusion of the substance

Here, the mass of the ice is

m = 5 g = 0.005 kg

And the specific latent heat of fusion of ice is

$\lambda_f = 334,000 J/kg$

Assuming that the ice is already at melting point, the thermal energy needed to melt the ice is

$Q=(0.005)(334,000)=1670 J$

Learn more about specific heat:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

You might be interested in

Samantha is checking the weather for her upcoming trip to Mexico City. The weather forecast predicts a high-pressure system for

Zanzabum

Calm, sunny days with wind moving away from the center.

5 0

3 years ago

Read 2 more answers

Simone is walking her dog on a leash. The dog is pulling with force of 34 N to the right and simone is pulling backward with a f

e-lub [12.9K]

I do not understand the full question, however if you are wondering which way Simone and the dog will go, they will go right because the force of 34 N from the dog is higher than the force of 16 N from Simone.

4 0

3 years ago

In the two-slit experiment, monochromatic light of wavelength 600 nm passes through a 19) pair of slits separated by 2.20 x 10-5

kumpel [21]

Explanation:

It is given that,

Wavelength of monochromatic light, $\lambda=600\ nm=6\times 10^{-7}\ m$

Slits separation, $d=2.2\times 10^{-5}\ m$

(a) We need to find the angle corresponding to the first bright fringe. For bright fringe the equation is given as :

$d\ sin\theta=n\lambda$ , n = 1

$\theta=sin^{-1}(\dfrac{\lambda}{d})$

$\theta=sin^{-1}(\dfrac{6\times 10^{-7}}{2.2\times 10^{-5}})$

$\theta=1.56^{\circ}$

(b) We need to find the angle corresponding to the second dark fringe, n = 1

So, $d\ sin\theta=(n+\dfrac{1}{2})\lambda$

$sin\theta=\dfrac{3\lambda}{2d}$

$\theta=sin^{-1}(\dfrac{3\lambda}{2d})$

$\theta=sin^{-1}(\dfrac{3\times 6\times 10^{-7}}{2\times 2.2\times 10^{-5}})$

$\theta=2.34^{\circ}$

Hence, this is the required solution.

4 0

4 years ago

A testable question is a question that _____. A. might be asked on a science test B. can be answered with either a yes or no C.

Cloud [144]

Answer:

D. can be answered by gathering observations.

Explanation:

4 0

3 years ago

2. What energy source produces most of the electrical energy in the United States?

Minchanka [31]

Answer:

Nat gas

Explanation:

Approx:

Natural gas 38% coal 21% oil 19%

6 0

2 years ago