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3 years ago

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I=\sqrt{-1}i= −1 i, equals, square root of, minus, 1, end square root, what is the sum (7+3i)+(-8+9i)(7+3i)+(−8+9i)left parent

hesis, 7, plus, 3, i, right parenthesis, plus, left parenthesis, minus, 8, plus, 9, i, right parenthesis?

1 answer:

nata0808 [166]3 years ago

4 0

We can simply add the expression to simplify the expression. So,

(7+3i)+(-8+9i) =7 +3i -8+9i Get rid of paranthesis.

=(7-8)+(3i+9i) Group the like terms.

= -1 + 12i

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The standard deviation of X is of:

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A similar problem is given at brainly.com/question/24261244

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1 year ago

Which point would be a solution to the system of linear inequalities ?

brilliants [131]

Answer:

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Step-by-step explanation:

we have

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$y\geq -\frac{5}{2}x+5$ ---> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

<u><em>Verify each point</em></u>

Substitute the value of x and the value of y of each ordered pair in the inequality A and in the inequality B

case 1) (0,-1)

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$-1\leq \frac{4}{3}(0)+5$

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Inequality B

$-1\geq -\frac{5}{2}(0)+5$

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therefore

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case 2) (0,3)

Inequality A

$3\leq \frac{4}{3}(0)+5$

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Inequality B

$3\geq -\frac{5}{2}(0)+5$

$3\geq 5$ ----> is not true

therefore

The ordered pair is not a solution of the system

case 3) (-6,-6)

Inequality A

$-6\leq \frac{4}{3}(-6)+5$

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Inequality B

$-6\geq -\frac{5}{2}(-6)+5$

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therefore

The ordered pair is not a solution of the system

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Inequality A

$-6\leq \frac{4}{3}(12)+5$

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Inequality B

$-6\geq -\frac{5}{2}(12)+5$

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therefore

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3 years ago