An electromagnet is a device that sends electricity through a coil of wire to produce a magnetic field. This leads to a magnet that can be controlled - turned on and off with the flip of a switch, or increased or decreased in strength. The coils are often wrapped around a regular magnet to make it stronger.
Answer:
-969.06
-286.74
698.7
-115.6, 12.9
-139.9, 12.9
Explanation:
Given that
Speed v, wrt y = -24.3 m/s
Speed v, wrt x = 12.9 m/s
time t, = 11.8 s
a
Using the formula
H(t) = ut - 1/2gt², where u = v wrt y
H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²
H(t) = -286.74 - 682.28
H(t) = -969.06 m
b
H = ut, where u = v wrt y
H = -24.3 * 11.8
H = -286.74 m
H(1) = -969.06 - -286.74 = -682 m
c
Horizontal displacement, x = vt. Where v = v wrt x
x = 12.9 * 11.8
x = 152.22 m
d = √(H1² + x²)
d = √682² + 152²
d = 465124 + 23104
d = √488228
d = 698.7 m
d
Vertical component =
-gt - 0 =
-9.8 * 11.8 = -115.6
Horizontal component =
v wrt x - 0
12.9 - 0 = 12.9
e
Vertical component =
-gt - v wrt y =
-9.8 * 11.8 - 24.3 = -139.9
Horizontal component =
v wrt x - 0 =
12.9 - 0 = 0
Answer:
Explanation:
a )
from lens makers formula
f is focal length , r₁ is radius of curvature of one face and r₂ is radius of curvature of second face
putting the values
1.462 = 2 - 1 / r₂
1 / r₂ = .538
r₂ = 1.86 cm .
= 18.6 mm .
b )
object distance u = 25 cm
focal length of convex lens f = 1.8 cm
image distance v = ?
lens formula
.5555 - .04
= .515
v = 1.94 cm
c )
magnification = v / u
= 1.94 / 25
= .0776
size of image = .0776 x size of object
= .0776 x 10 mm
= .776 mm
It will be a real image and it will be inverted.
Answer:
2.27 cm
2.5 cm
Explanation:
u = Object distance = 25 cm
v = Image distance = 2.5 cm
f = Focal length
Lens Equation
The minimum effective focal length of the focusing mechanism of the typical eye is 2.27 cm
when 
The maximum effective focal length of the focusing mechanism of the typical eye is 2.5 cm
