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LenKa [72]
4 years ago
8

This one please... okay:)

Mathematics
1 answer:
AVprozaik [17]4 years ago
7 0
<span>2x+2y=32 and xy=60
--> x+y=16 and xy=60
--> y = 16-x 
--> x(16-x)=60

 

so we have a quadratic, which needs to be solved. Hopefully by factorization. If not..the quadratic formula. 

1x60
2x30
3x20

4x15
5x12
6x10 

looking at these, 6 and 10 can add to make 16, so 

(x-10)(x-6) = 0
so x-10=0 OR x-6=0
so x=10 OR x=6 

so, basically we have x=10, so y=6
or we have the opposite, x=6 and y=10 
hope this helps</span><span />
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serg [7]

Answer:

\large\boxed{3x^3+23x^2+63x+55}

Step-by-step explanation:

\text{Use FOIL:}\\\\(a+b)(c+d)=ac+ad+bc+bd

(3x+5)(x^2+6x+11)\\\\=(3x)(x^2)+(3x)(6x)+(3x)(11)+(5)(x^2)+(5)(6x)+(5)(11)\\\\=3x^3+18x^2+33x+5x^2+30x+55\qquad\text{combine like terms}\\\\=3x^3+(18x^2+5x^3)+(33x+30x)+55\\\\=3x^3+23x^2+63x+55

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Step-by-step explanation

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