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son4ous [18]
3 years ago
13

Two examples of ways that physicists model the physical world

Physics
2 answers:
aliya0001 [1]3 years ago
6 0
They build small-scale replicas . physicists build computer simulations.
AVprozaik [17]3 years ago
4 0

Answering the question, three examples of ways that physicists model the physical world include:

  • Diagrams
  • Equations
  • Computer simulations

Computer simulations refer to the reproduction of behavior of a system with the use of a computer to simulate the results of a mathematical model that is linked with the system.

<h2>Further Explanation</h2>

Computer simulations are a tool that is very useful for mathematical modeling in various natural systems in physics.

Physicists write the rule of our universe using equations. Equations are an aspect of one of the models used by physicists to explain a particular situation.

Physicists use a diagram to convey information. It is a symbolic representation of information with the use of visualization techniques. Diagram provides other means for people to better understand information and process its importance.

Physics predictions about the physical world mainly depend on numerical stimulation, mathematics and empirical observations and Physicists models the physical world based on invariances and laws which are built on mathematical models.

The purpose of physics is to explain or describe everything around us. It described virtually everything around us accurately by deploring the law of physics.

However, physics is considered a natural science because it is based on mathematical analysis which is geared towards findings qualitative physical law for the physical world.

LEARN MORE:

  • examples of ways that physicists model the physical world brainly.com/question/10869755

KEYWORDS:

  • physicists
  • physics
  • models
  • physical world
  • computer simulations
  • diagrams
  • equations
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Bart ran 5000 meters from the cops and had an average speed of 6 meters/second before he got caught. How long did he run?
atroni [7]

Answer:

thats is a long time

Explanation:

maybe 1 hour

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2 years ago
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Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average
aalyn [17]

Answer:

7,166 hrs =430  minutes

Explanation:

Since both train are on the same track, going one towards the other, the relative speed is the addition of both, then the time they need to meet, and consistently crash, is the time that (65mph + 55 mph)=120mph need to travel the total distance of 860 miles, of course in this case one part is traveled by the first train and the rest by the other. Then to find the time we use a three rule

1 h --->120mi

X ---->860mi, then X=(860 mi* 1h)/120 mi = 43/6 hrs= 7,16666 hrs, turning this into minutes need that we notice 1h=60min, then 43/6 hrs *60 min/hrs = 430 minutes.

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3 years ago
What is the velocity of a wave that has a frequency of 400Hz and a wavelength of 0.5 meters
iren2701 [21]

Answer: 12

Explanation:

Let’s take for instance the case of a wave with a frequency of 400 Hz going through a material at a speed of .5 m/s. The wavelength result is 12 m. Wave velocity (m/s) = Frequency (Hz) x Wavelength (m)

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2 years ago
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An object is thrown straight up with an initial velocity of 10 m/s, and there is an air resistance force causing an acceleration
lana [24]

Answer:

Vf= 7.29 m/s

Explanation:

Two force act on the object:

1) Gravity

2) Air resistance

Upward motion:

Initial velocity = Vi= 10 m/s

Final velocity = Vf= 0 m/s

Gravity acting downward =  g = -9.8 m/s²

Air resistance acting downward = a₁ = - 3 m/s²

Net acceleration = a = -(g + a₁ ) = - ( 9.8 + 3 ) = - 12.8 m/s²

( Acceleration is consider negative if it is in opposite direction of velocity )

Now

2as = Vf² - Vi²

⇒ 2 * (-12.8) *s = 0 - 10²

⇒-25.6 *s = -100

⇒ s = 100/ 25.6

⇒ s = 3.9 m

Downward motion:

Vi= 0 m/s

s = 3.9 m

Gravity acting downward =  g = 9.8 m/s²

Air resistance acting upward = a₁ = - 3 m/s²

Net acceleration = a = g - a₁  =  9.8 - 3  = 6.8 m/s²

Now

2as = Vf² - Vi²

⇒ 2 * 6.8 * 3.9 = Vf² - 0

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8 0
3 years ago
To construct a solenoid, you wrap insulated wire uniformly around a plastic tube 7.1 cm in diameter and 57 cm in length. You wou
ASHA 777 [7]

Answer:

We need about 8769 meters of wire to produce a 2.6 kilogauss magnetic field.

Explanation:

Recall the formula for the magnetic field produced by a solenoid of length L. N turns, and running a current I:

B=\mu_0\,\frac{N}{L} \,I

So, in our case, where B = 2.6 KG = 0.26 Tesla; I is 3 amperes, and L = 0.57 m, we can find what is the number of turns needed;

B=\mu_0\,\frac{N}{L} \,I\\0.26=4\,\pi\,10^{-7}\frac{N}{0.57} \,3\\N=\frac{0.26*0.57\,10^7}{12\,\pi} \\N=39311.27

Therefore we need about 39312 turns of wire. Considering that each turn must have a length of \pi\,D, where D is the diameter of the plastic cylindrical tube, then the total length of the wire must be:

Length=39312\,(\pi\,D)=39312\,(\pi\,0.071)\approx 8768.66\,\,m

We can round it to about 8769 meters.

5 0
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