Question

15 points for 2 questions

Answer 1

I believe the answer would be c because i think that you multiply the 2

Answer 2

1. D) 300 J

The work done by a constant force is given by:

$W=Fdcos \theta$

where F is the force applied, d is the distance, and $\theta$ is the angle between the direction of the force and the direction of motion.

In this problem, F=200 N, d=1.5 m while $\theta=0^{\circ}$, because the force is parallel to the motion of the box, therefore the work done is

$W=(200 N)(1.5 m)(cos 0^{\circ})=300 J$

2. C) 48,000 J

We can use the same formula used in the previous part of the problem:

$W=Fdcos \theta$

In this case:

F=480 N

d=100 m

$\theta=0^{\circ}$

So the work done is

$W=(480 N)(100 m)(cos 0)=48,000 J$