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nirvana33 [79]
2 years ago
11

15 points for 2 questions

Physics
2 answers:
Elden [556K]2 years ago
8 0
I believe the answer would be c because i think that you multiply the 2
amid [387]2 years ago
6 0

1. D) 300 J

The work done by a constant force is given by:

W=Fdcos \theta

where F is the force applied, d is the distance, and \theta is the angle between the direction of the force and the direction of motion.

In this problem, F=200 N, d=1.5 m while \theta=0^{\circ}, because the force is parallel to the motion of the box, therefore the work done is

W=(200 N)(1.5 m)(cos 0^{\circ})=300 J


2. C) 48,000 J

We can use the same formula used in the previous part of the problem:

W=Fdcos \theta

In this case:

F=480 N

d=100 m

\theta=0^{\circ}

So the work done is

W=(480 N)(100 m)(cos 0)=48,000 J

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Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

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The mutual force between the two point charges is 319.64 N

Explanation:

Given;

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F = \frac{k|q_1||q_2|}{r^2}

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