The urethra extends from the:

Physics

1 answer:

katrin [286]2 years ago

8 0

From the bladder and goes through the male genitalia.

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Using the scientific definition of work, does moving an object a greater amount of distance always require a greater amount of w

tester [92]

The answer is no. If you are dealing with a conservative force and the object begins and ends at the same potential then the work is zero, regardless of the distance travelled. This can be shown using the work-energy theorem which states that the work done by a force is equal to the change in kinetic energy of the object.
W=KEf−KEi
An example of this would be a mass moving on a frictionless curved track under the force of gravity.
The work done by the force of gravity in moving the objects in both case A and B is the same (=0, since the object begins and ends with zero velocity) but the object travels a much greater distance in case B, even though the force is constant in both cases.

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Two horizontal curves on a bobsled run are banked at the same angle, but one has twice the radius of the other. The safe speed (

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Answer:

safe speed for the larger radius track u= √2 v

Explanation:

The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.

Also given that r_1= smaller radius

r_2= larger radius curve

r_2= 2r_1..............i

let u be the speed of larger radius curve

now, $\sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}$ ................ii

form i and ii we can write

$v^2= \frac{1}{2} u^2$

⇒u= √2 v

therefore, safe speed for the larger radius track u= √2 v

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A nail is hit with a hammer. Which type of contact force has been applied?

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Applied force I think.

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A 50 kg woman, riding on a 10 kg cart, is moving east at 5.0 m/s. the woman jumps off the cart and hits the ground running at 7.

pav-90 [236]

To answer this question, we will use the law of conservation of momentum which states that:
(m1+m2)Vi = m1V1 + m2V2 where:
m1 is the mass of the woman = 50 kg
m2 is the mass of the cart = 10 kg
Vi is the initial velocity (of woman and cart combined) = 5 m/sec
V1 is the final velocity of the woman = 7 m/sec
V2 is the final velocity of the cart that we need to calculate

Substitute with the givens in the above equation to get the final velocity of the cart as follows:
(50+10)(5) = (50)(7) + (10)V2
10V2 = -50
V2 = -5 m/sec
Note that the negative sign indicates that the cart is moving in an opposite direction to the others.

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The farthest major planet from the sun is Neptune

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