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3 years ago

The number of mushrooms needed by a pizza restaurant is given by the

Physics

1 answer:

creativ13 [48]3 years ago

6 0

Answer: 24

Explanation:

Given the following equation:

$g=3n$

Where $g$ is the number of mushrooms in a pizza and $n$ the number of pizzas.

If we know the restaurant will make 8 pizzas ( $n=8$ ), then:

$g=3(8)$

$g=24$ This is the needed number of mushrooms for 8 pizzas

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vladimir2022 [97]

V= 1/3 π r²h
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3 years ago

Read 2 more answers

PLEASE HELP While the Earth is revolving around the sun, less direct sunlight is reaching the Northern Hemisphere than the South

jekas [21]

Answer:

Winter

Explanation:

Earth Rotates about an axis

7 0

3 years ago

A solid uniform disk of diameter 3.20 m and mass 42 kg rolls without slipping to the bottom of a hill, starting from rest. If th

Korvikt [17]

Answer:

A(3.56m)

Explanation:

We have a conservation of energy problem here as well. Potential energy is being converted into linear kinetic energy and rotational kinetic energy.

We are given ω= 4.27rad/s, so v = ωr, which is 6.832 m/s. Place your coordinate system at top of the hill so E initial is 0.

Ef= Ug+Klin+Krot= -mgh+1/2mv^2+1/2Iω^2

Since it is a solid uniform disk I= 1/2MR^2, so Krot will be 1/4Mv^2(r^2ω^2= v^2).

Ef= -mgh+3/4mv^2

Since Ef=Ei=0

Mgh=3/4mv^2

gh=3/4v^2

h=0.75v^2/g

plug in givens to get h= 3.57m

5 0

3 years ago

On the moon, the acceleration of gravity is 1.6 m/s2. If an object has a

Amanda [17]

Answer:

5.1 kg

Explanation:

Its mass on the moon is 5.1 kg because mass is an intrinsic property of a material and does not change with location. Although, its weight might vary because its acceleration of gravity g is dependent on the mass M and radius r of the planet(in this case, moon) involved g = GM/r². Since weight W = mg is dependent o g, weight varies but mass remains constant.

4 0

3 years ago

Two racecars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the

Alenkasestr [34]

Answer:

The acceleration of car 2 is four times of the acceleration of car 1.

Explanation:

The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :

$a=\dfrac{v^2}{r}$

In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.

So,

$\dfrac{a_1}{a_2}=\dfrac{v_1^2}{v_2^2}$

1 and 2 represent car 1 and car 2 respectively.

$v_2=2v_1$

So,

$\dfrac{a_1}{a_2}=\dfrac{v_1^2}{(2v_1)^2}\\\\\dfrac{a_1}{a_2}=\dfrac{v_1^2}{4v_1^2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{4}\\\\a_2=4\times a_1$

So, the acceleration of car 2 is four times of the acceleration of car 1.

4 0

3 years ago