If population in 2025 is 450 (in thousands)
15 years prior (2010, it is 450 - 15(4) or 390
now in years (p) after this date population increases 4 (in thousands) times the number of years.
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<span>so formula would be p = 390 + 4p
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Answer:
Least to greatest: -5 1/2, -5.2, -5, -5/2, 5.5
Answer:
4 11/20
Step-by-step explanation:
Using bidMAs Multiplication comes first before addition
2/5 * 7/6 = 14/30
7/6 * 7/2 = 49/12
Make denominators equal
14/30 * 2 = 28/60
49/12 * 5 = 245/60
Then add
28/60 + 245/60 = 273/60
Finally convert improper into mixed fraction
4 11/20
<h3>Answer:</h3>
c) there are infinitely many solutions
<h3>Explanation:</h3>
Add x to the <em>first equation</em> to put it in standard form:
... x + y = 3
Divide the <em>second equation</em> by the common factor of all terms, 2, to put it in standard form:
... x + y = 3
These two equations describe the same line. Every point on the line is a solution to both equations, so there are infinitely many solutions. (We say these equations are "dependent.")
