Answer is 26 13/64
first u need to simplify mixed number then multiply them all
43/8*3*13/8=1677/64
<h3>
<u>Explanation</u><u>:</u></h3>
- Calculate the slope with two given coordinate points by using rise over run.

Let these points



Substitute the value of m in the equation.

- Substitute any coordinate points that are given or part of the graph in the equation.


- Solve the equation for b-term.

- Rewrite the equation by substituting the value of b in the equation.

<h3>
<u>Answer</u></h3>

<em>If</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>any</em><em> </em><em>questions</em><em> </em><em>related</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>answer</em><em>,</em><em> </em><em>feel</em><em> </em><em>free</em><em> </em><em>to</em><em> </em><em>ask</em><em> </em><em>via</em><em> </em><em>comment</em><em>.</em>
Answer:
15% off
Step-by-step explanation:
We know we paid $25.50 of the original $30. We can divide these two numbers
. This is means we paid 85% of the original price. The discount percentage is the remaining percentage from 85 to 100 which is 15. The pants were 15% off.
Answer:


Step-by-step explanation:
Given

Solving (a): Write as inverse function

Represent a(d) as y

Swap positions of d and y

Make y the subject


Replace y with a'(d)

Prove that a(d) and a'(d) are inverse functions
and 
To do this, we prove that:

Solving for 

Substitute
for d in 




Solving for: 

Substitute 5d - 3 for d in 

Add fractions



Hence:

Answer:
PS = 10 
Step-by-step explanation: