The tension in the swing's chain at the bottom of the swing is 178.35 N.
The given parameters:
- Mass of the girl, m = 27 kg
- Speed of the girl, v = 3 m/s
- Radius of the circle, r = 4 m
The tension in the swing's chain at the bottom of the swing is calculated as follows;

Thus, the tension in the swing's chain at the bottom of the swing is 178.35 N.
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The dimension of K is M/ T^2
according to the question T=2π square root ofm/k here 2 pi is constant so
T= root of m /k and root of k = root of m/ T now by squaring on both the sides we get the answer k= M/ T^2
complete question :
A spring is hanging down from the ceiling, and an object of mass m is attached to the free end. The object is pulled down, thereby stretching the spring, and then released. The object oscillates up and down, and the time T required for one complete up-and-down oscillation is given by the equation T=√2πm/k, where k is known as the spring constant. What must be the dimension of k for this equation to be dimensionally correct?
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Explanation:
physical quantity is any physical property that can be qualified that,is, be measured using numbers e.g mass, amount of substance,time and length
Answer:
The percentage change in resistance of the wire is 69%.
Explanation:
Resistance of a wire can be determined by,
R = (ρl) ÷ A
Where R is its resistance, l is the length of the wire, A its cross sectional area and ρ its resistivity.
When the wire is stretched, its length and area changes but its volume and resistivity remains constant.
= 1.3l, and
= 
So that;
= (ρ
) ÷
= (ρ × 1.3l) ÷ (
)
= (1.3lρ) ÷ (
)
=
× [(ρl) ÷ A]
= 1.69R (∵ R = (ρl) ÷ A)
= 1.69R
Where
is the new resistance,
is the new length, and
is the new area after stretching the wire.
The change in resistance of the wire =
- R
= 1.69R - 1R
= 0.69R
The percentage change in resistance =
× 100
= 0.69 × 100
= 69%
The percentage change in resistance of the wire is 69%.