dashed lines<span> represent bonds away from the viewer.</span>
Okay, haven't done physics in years, let's see if I remember this.
So Coulomb's Law states that
so if we double the charge on
and double the distance to
we plug these into the equation to find
<span>
</span>
So we see the new force is exactly 1/2 of the old force so your answer should be
if I can remember my physics correctly.
Answer:
The net force is 21 N, and the bag will go to the right.
Explanation:
You can find the net force by adding both values of the boy and the girl, and then subtracting four from it. You can also figure out which direction its moving by looking at which side is exerting the most force, which would be the right side.
<em>Hope </em><em>it </em><em>helps</em><em>!</em>
Answer:
a) Height of the antenna (in m) for a radio station broadcasting at 604 kHz = 124.17 m
b)Height of the antenna (in m) for radio stations broadcasting at 1,710 kHz =43.86 m
Explanation:
(a) Radiowave wavelength= λ = c/f
As we know, Radiowave speed in the air = c = 3 x 10^8 m/s
f = frequency = 604 kHz = 604 x 10^3 Hz
Hence, wavelength = (3x10^8/604x10^3) m
λ
= 496.69 m
So the height of the antenna BROADCASTING AT 604 kHz = λ /4 = (496.69/4) m
= 124.17 m
(b) As we know , f = 1710 kHz = 1710 x 10^3 Hz (1kHZ = 1000 Hz)
Hence, wavelength = λ = (3 x 10^8/1710 x 10^3) m
λ= 175.44 m
So, height of the antenna = λ /4 = (175.44/4) m
= 43.86 m
