Answer:
16.9000000000000001 J
Explanation:
From the given information:
Let the initial kinetic energy from point A be = 1.9000000000000001 J
and the final kinetic energy from point B be = ???
The charge particle Q = 6 mC = 6 × 10⁻³ C
The change in the electric potential from point B to A;
i.e. V_B - V_A = -2.5 × 10³ V
According to the work-energy theorem:
-Q × ΔV = ΔK
Answer:
1428.6m/s²
Explanation:
Given parameters:
Force applied on the body = 40N
Mass of the body = 28g
1000g = 1kg
28g will therefore be 0.028kg
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use the expression derived from Newton's second law of motion.
Force = mass x acceleration
Insert the parameters and solve;
40 = 0.028 x acceleration
Acceleration = = 1428.6m/s²