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2 years ago

How much power is generated if 375 J of work is done in 15 s?

Physics

1 answer:

erma4kov [3.2K]2 years ago

7 0

Answer: 25 watt

Explanation:

Given,

Work= 375 j

Time= 15

So, power = W÷t

= 375 ÷ 15

= 25 watt

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PLEASE SOMEONE ANSWER!!! thank you so so so much!!!!

Oduvanchick [21]

Answer:

As much I know the gravity on moon is 1.62m/s२.

7 0

3 years ago

In a lab, four balls have the same velocities but different masses.

olya-2409 [2.1K]

Answer:

New Momentum of Ball B $=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

<u>Explanation:</u>

Given:

Mass of Ball A=1kg

Mass of Ball B= 2kg

Mass of Ball C=5kg

Mass of Ball D=7kg

Velocities of A=B=C=D=2.2 $\frac{m}{s}$

Momentum of Ball A=2.2 $\frac{k g m}{s}$

Momentum of Ball B=4.4 $\frac{k g m}{s}$

Momentum of Ball C=11 $\frac{k g m}{s}$

Momentum of Ball D=15 $\frac{k g m}{s}$

To Find:

Change in Momentum When of Ball B gets tripled

Solution:

Though all balls have same velocity, thus we get

Velocities of A=B=C=D=2.2 $\frac{m}{s}$

Initial Momentum of Ball B=4.4 $\frac{k g m}{s}$

If the Mass of Ball B gets tripled;

We get New Mass of Ball B=3×Actual Mass of the ball

=3×2=6kg

Thus we get Mass of Ball B=6kg

According to the formula,

Change in momentum of Ball B $\Delta p=m \times \Delta v$

Where $\Delta p$ =change in momentum

m=mass of the ball B

$\Delta v$ =change in velocity ball B

And $\Delta v=v,$ since all balls, have same velocity

Thus the above equation, changes to

$\Delta p=m \times v$

Substitute all the values in the above equation we get

$\Delta p=6 \times 2.2$

$=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

Result:

Thus the New Momentum of ball B $=13.2 \frac{\mathrm{kgm}}{\mathrm{s}}$

3 0

2 years ago

Read 2 more answers

A clock moves past you at a speed of 0.9 c. How much time passes for you for each second that elapses on the moving clock?

Zigmanuir [339]

Answer:

Explanation:

Time dilation formula is

T = T₀ / √ 1-v²/c²

T₀ is time elapsed in moving reference , T time elapsed in stationary reference.

Here T₀ = 1 second

T = 1/√ 1-0.9² = 1/.4358 = 2.3 second

So 2.3 second will pass for each second on moving reference.

6 0

3 years ago

A 21 g ball is shot from a spring gun whose spring has a force constant of 579 N/m. The spring can be compressed 1 cm. How high

vodka [1.7K]

Answer:

The answer to the question is

The ball will go 0.14 meters high if the gun is aimed vertically

Explanation:

The energy in the spring → Energy, E = $\frac{1}{2}kx^2$

Where E = energy in the spring

k = Spring constant

x = Spring compression or stretch

Therefore E = $\frac{1}{2} 579*0.01^2 = 0.02895 J$

The spring energy is transferred to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed

Kinetic energy = KE = $\frac{1}{2}mv^2$

From which v = $\sqrt{\frac{2*KE}{m} }$ = $\sqrt{\frac{2*0.02895}{0.021} }$ = 1.66 m/s

from v² =u² - 2·a·S

Where v = final velocity = 0 m/s

u = initial velocity = 1.66 m/s

a = g = Acceleration due to gravity

S = height

Therefore 0 = 1.66² - 2×9.81×S

or S = 1.66² ÷ (2×9.81) = 0.14 m

7 0

2 years ago

In order to decrease the friction an object experiences, you can either change

Kipish [7]

Answer:

Reduce its weight

Explanation:

For an object on a flat surface, the maximum force of friction experienced by the object is given by:

$F = \mu W$

where

$\mu$ is the coefficient of friction

W is the weight of the object

As we can see from the formula, there are two ways of reducing the friction:

- Decreasing $\mu$ --> this coefficient depends on the material and on the roughness of the surface, so this can be changed by changing the properties of the surface

- Decreasing W, the weight --> this can be done by reducing the mass of the object

8 0

3 years ago