It begins with a kick-off
Density is mass per unit of volume, usually measured in g/cm³. So first determine the volume of the cylinder:
<em>v</em> = <em>π</em> <em>r </em>² <em>h</em> = <em>π</em> ((39.0 mm) / 2)² (39.0 mm)
<em>v</em> = 59,319/4 <em>π</em> mm³ ≈ 46,589 mm³ ≈ 46.589 cm³
Then the density is
<em>ρ</em> = <em>m</em> / <em>v</em>
<em>ρ</em> = (1 kg) / <em>v</em> = (1000 g) / <em>v</em>
<em>ρ</em> ≈ 21.464 g/cm³
Or, if you want to preserve the given units, that's
<em>ρ</em> ≈ 0.00002146 kg/mm³
Answer:
Option C. 3 m/s
Explanation:
From the question it is stated that we can neglect the force of air resistance, therefore there is no force acting on the ball horizontally. From Newton's first law of motion an object will remain at rest or in uniform motion unless acted upon by an external force. thus the ball velocity will remain 3m/s.
The acceleration is inmx/s2
