What is the most common consumed Halloween candy in the us after chocolate

Hi guys . I'm having some troubles with physics and chemistry .

Otrada [13]

Answer:

physics and math tutor

Save my exams

Explanation:

hii! for PTM(physics and math tutor) you simply type in the search bar for example in. physics Units and measurements past papers.Then the first option would be PTM(physics and math tutor) and you click on it and it would give you on the left side Revision Notes, flashcards and practice questions. This site has helped me so much and I hope this helps you too (by the way PTM has for all 3 sciences and math too) just simply type the lesson name along with past paper and click on the first link and you'll get yourself your answers!!!! hopefully this helps!:))

6 0

3 years ago

a 2kg ball moving at speed 5m/s hits a wall .the force exerted by the wall on the ball is 100n .if the collision is perfectly el

levacccp [35]

Answer:

0.2s

force = change in momentum/ time

time = change in momentum/time

Explanation:

first, let's find the change in momentum

pf-pi

5×(-2) - 5× 2

-20kgm/s = 20kgm/s(by changing the direction of whole system)

time = change in momentum/time

20/100

4 0

3 years ago

How does speed effect momentum?

drek231 [11]

Momentum = mass * speed
Speed is proportional to momentum; i.e. having twice the speed would result in double the momentum, a lower speed = smaller momentum, etc

7 0

3 years ago

In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope

zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude $g$ .

If we have the initial velocity $v_o$ and its angle $\theta$ , we can obtain the vertical component of the velocity $v_{oy}$ using trigonometry:

$v_{oy}=v_osin\theta$

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

$v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }$

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

$g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

Finally, from the equation of horizontal motion with constant speed, we have that:

$x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

$v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s} }{9.8\frac{m}{s^{2} } } =7.49m$

In words, the projectile travels 7.49m horizontally before it lands.

8 0

4 years ago

Could someone please explain isotopes, and what they do/are? If not thats fine, thank you

Firdavs [7]

Answer:

each of two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei, and hence differ in relative atomic mass but not in chemical properties; in particular, a radioactive form of an element.

"some elements have only one stable isotope"

Explanation:

there ya go! Pls give me brainliest!

7 0

3 years ago