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Natasha_Volkova [10]
2 years ago
8

Question: the distance of the car can move by velocity 15 m/s for time 5s is : Physics

Physics
1 answer:
tangare [24]2 years ago
7 0

Answer:

c) 2.05

Explanation:

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A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav
uysha [10]
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0
3 years ago
Which of the following scientists won a noble prize of pioneering work in the study of the evolution of stars?
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Subrahmanyan chandrasekhar
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3 years ago
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The PE of the box that is on a 2.0 m high self is 1600 J. What is the power expelled to lift the box to this height in 10.0 seco
Pani-rosa [81]

Answer:

  160 W

Explanation:

Power is the ratio of work to time:

  (1600 J)/(10 s) = 160 J/s = 160 W

7 0
2 years ago
A car is driving 55 miles per hour east. The car changes direction to head north but still travels at 55 miles per hour. Which i
bezimeni [28]

Answer:

Just as distance and displacement have distinctly different meanings (despite their similarities), so do speed and velocity. Speed is a scalar quantity that refers to "how fast an object is moving." Speed can be thought of as the rate at which an object covers distance. A fast-moving object has a high speed and covers a relatively large distance in a short amount of time. Contrast this to a slow-moving object that has a low speed; it covers a relatively small amount of distance in the same amount of time. An object with no movement at all has a zero speed.

7 0
2 years ago
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Two in-phase loudspeakers, which emit sound in all directions, are sitting side by side. One of them is moved sideways by 4.0 mm
loris [4]

Answer:

4.4721m

Explanation:

#Use Pythagorean theorem to find the distance between the two speakers:

a^+b^2=c^2\\4^2+2^2=d^2\\\sqrt{20}\ mm=d

There are antinodes 1/4,1/2 and 3/4 of the distance between speakers.

The greatest antinode is 3/4-1/4=1/2

#Distance between consecutive antinodes is:

0.5\times \sqrt{20}=\lambda/2\\\\\lambda=4.4721m

Hence, the maximum possible wavelength of the sound waves is 4.4721m

6 0
3 years ago
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