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saul85 [17]
3 years ago
12

In a nuclear power plant, the nuclear reaction is kept from going critical by keeping the rate of reaction safe how to do the co

ntrol rod figure into this.
Physics
1 answer:
Svetlanka [38]3 years ago
5 0
The control rods absorb some of the neutrons that are
flying around, so those neutrons don't get to smash into
more Uranium nuclei and start more fissions.

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A semi has a net force of 13,000 N and is accelerating at a rate of 6.5 m/s^2. What is the mass of the semi? *
Evgen [1.6K]

Example 1: An 850-kg car is accelerating at a rate of 2.4m/s2 to the right along a ... 2) A nonzero net force ΣF acting on mass M causes an acceleration a in it such that ΣF = Ma. The acceleration has the same direction as the applied net force. ... (b) Knowing that the crate is being pushed to the left by a 53-N force

4 0
3 years ago
A swimming pool contains x (less than 0.02) grams of chlorine per cubic meter. the pool measures 5 meters by 50 meters and is 2
zubka84 [21]
The solution for this problem would be:(10 - 500x) / (5 - x) 
so start by doing: 
x(5*50*2) - xV + 5V = 0.02(5*50*2) 
500x - xV + 5V = 10 
V(5 - x) = 10 - 500x 
V = (10 - 500x) / (5 - x) 
(V stands for the volume, but leaves us with the expression for x)
3 0
3 years ago
A 215-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope a
Misha Larkins [42]

Answer:

303.9481875 N

Explanation:

t = Time taken = 2 seconds

F = Force

r = Radius = 1.5 m

I = Moment of Inertia

\alpha = Angular Acceleration

Torque

\tau=F\times r

\tau=I\times \alpha

\\\Rightarrow F\times r=I\times \alpha\\\Rightarrow F=\frac{I\times \alpha}{r}

Angular velocity

\omega=rev/s\times 2\pi\\\Rightarrow \omega=0.6\times 2\pi\\\Rightarrow \omega=3.76991\ rad/s

Angular acceleration

\alpha=\frac{\omega}{t}\\\Rightarrow \alpha=\frac{3.76991}{2}\\\Rightarrow \alpha=1.88495\ rad/s^2

I=\frac{1}{2}mr^2\\\Rightarrow I=\frac{1}{2}215\times 1.5^2\\\Rightarrow I=241.875\ kgm^2

F=\frac{I\times \alpha}{r}\\\Rightarrow F=\frac{241.875\times 1.88495}{1.5}\\\Rightarrow F=303.9481875\ N

The magnitude of the force to stop the merry-go-round is 303.9481875 N

3 0
3 years ago
A simple generator is used to generate a peak output voltage of 19.0 V . The square armature consists of windings that are 6.65
salantis [7]

One of the efficient concepts that can help us find the number of turns of the cable is through the concept of induced voltage or electromotive force given by Faraday's law. The electromotive force or emf can be described as,

\epsilon = NBA\omega

Where,

N = Number of loops

B = Magnetic Field

A = Cross-sectional Area

\omega = Angular velocity

Re-arrange to find N,

N = \frac{\epsilon}{BA\omega}

Our values are given as,

\epsilon = 19V

B = 0.434T

\omega = 49.8\frac{rev}{s} (\frac{2\pi rad}{1 rev}) = 99.6\pi rad/s

A = (6.65*10^{-2})^2 m^2

Replacing at our equation we have:

N = \frac{\epsilon}{( 0.434)A\omega}

N = \frac{19}{( 0.434)((6.65*10^{-2})^2)(99.6\pi)}

N = 31.63 \approx 32

Therefore the number of loops of wire should be wound on the square armature is 32 loops

6 0
3 years ago
Generators use a magnetic field of which of the following to produce an electric current?
Scrat [10]
The answer is going to be magnetic domain
8 0
3 years ago
Read 2 more answers
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