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saul85 [17]
3 years ago
12

In a nuclear power plant, the nuclear reaction is kept from going critical by keeping the rate of reaction safe how to do the co

ntrol rod figure into this.
Physics
1 answer:
Svetlanka [38]3 years ago
5 0
The control rods absorb some of the neutrons that are
flying around, so those neutrons don't get to smash into
more Uranium nuclei and start more fissions.

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Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea
Kipish [7]

Answer:

6.5 m/s

Explanation:

We are given that

Distance, s=100 m

Initial speed, u=1.4 m/s

Acceleration, a=0.20 m/s^2

We have to find the final velocity at the end of the 100.0 m.

We know that

v^2-u^2=2as

Using the formula

v^2-(1.4)^2=2\times 0.20\times 100

v^2-1.96=40

v^2=40+1.96

v^2=41.96

v=\sqrt{41.96}

v=6.5 m/s

Hence, her final velocity at the end of the 100.0 m=6.5 m/s

5 0
3 years ago
Para que exista una fuerza se necesita cuando menos…
kozerog [31]

Answer:

Explanation:

No entiendo lo que quieres decir con eso

8 0
3 years ago
I have an astronomy question... Spinning up the solar nebula. The orbital speed of the material in the solar nebula at Pluto's a
attashe74 [19]
<span>The angular momentum of a particle in orbit is 

l = m v r 

Assuming that no torques act and that angular momentum is conserved then if we compare two epochs "1" and "2" 

m_1 v_1 r_1 = m_2 v_2 r_2 

Assuming that the mass did not change, conservation of angular momentum demands that 

v_1 r_1 = v_2 r_2 

or 

v1 = v_2 (r_2/r_1) 

Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have 

v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s

Therefore, </span> the orbital speed of this material when it was 40,000 AU from the sun is <span>4.875E-3 km/s.

I hope my answer has come to your help. Thank you for posting your question here in Brainly.
</span>
3 0
3 years ago
How does mass and material type effect thermal energy transfer
Vedmedyk [2.9K]
The mass contributes with the time of thermal energy transfer with respect to the material type  but most importantly the material type will determine rate at which the material absorbs the transfer of heat or thermal energy by either three types, conduction, convection and radiation.
4 0
3 years ago
Jason knows that the equation to calculate the period of a simple pendium T=2π√L/8, where T is the period, L is the length of th
erik [133]

Answer: L can be expressed in terms of g and f as

L = g/(2πf)^2

Explanation: Please see the attachments below

3 0
3 years ago
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