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hammer [34]
3 years ago
13

Compare the potential energy of a 5 lb ball at the top of a 5 foot hill and a 5 lb ball at the top of a 10 foot hill.

Physics
1 answer:
krek1111 [17]3 years ago
5 0
Potential energy is the energy possessed by a body at rest while the kinetic energy is the energy possessed by a body in motion.
Potential energy is given by mass× gravitational acceleration × height
         That is energy = mgh
For the first ball the potential energy is 2.268 ×10 ×5 = 113.4 J (5 lb = 2.268 kg)
          The second ball with the same mass will have 2.268 ×10 ×10 = 226.8 J
Thus, the potential energy is dependent on the height of a given body and therefore the ball at the 5 foot hill has less potential energy.

You might be interested in
A point charge q1 = 3.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 10 m.
UkoKoshka [18]

Answer:

a) 1.6 mN  b) -1.6 mN  c) -1.6 mN  d) 1.6 mN

Explanation:

The electrostatic force between 2 point charges, obeys the Coulomb's Law, that can be expressed as follows:

F₁₂ = k*q₁*q₂/(r₁₂)² (in magnitude)

The direction of the force, is along the  line that joins the  charges (along the x axis) and as q₁ and q₂ are of the same sign, aims away from both charges.

a) So, for the force on q₂, we have:

F₁₂ = 9*18*10⁻⁵ N = 1.6 mN (positive as it is aiming in the positive x direction)

b) The force on q1, according to Newton's 3rd Law, is just equal and opposite to the one on q2:

F₂₁ = (-9*18*10⁻⁵) N = -1.6 mN (towards the negative x direction, away from q1)

c) If q₂ were -6.0 μC, the force will be the same in magnitude, but as now both charges have different signs, they wil attract each other, so the direction of the forces will be exactly the opposite to the first case:

F₁₂ = -1.6 mN (going towards the origin, where q₁ is located)

F₂₁ =  1.6 mN (going in the positive x direction, towards q₂)

6 0
4 years ago
Read 2 more answers
The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that
pav-90 [236]

Answer:

The permittivity of rubber is  \epsilon  = 8.703 *10^{-11}

Explanation:

From the question we are told that

     The  magnitude of the point charge is  q_1 =  70 \ nC  =  70 *10^{-9} \  C

      The diameter of the rubber shell is  d = 32 \ cm  =  0.32 \ m

       The Electric field inside the rubber shell is  E =  2500 \ N/ C

The radius of the rubber is  mathematically evaluated as

              r =  \frac{d}{2} =  \frac{0.32}{2}  =  0.16 \ m

Generally the electric field for a point  is in an insulator(rubber) is mathematically represented as

         E =  \frac{Q}{ \epsilon }  *  \frac{1}{4 *  \pi r^2}

Where \epsilon is the permittivity of rubber

    =>     E  *  \epsilon  *  4 * \pi *  r^2 =  Q

   =>      \epsilon  =  \frac{Q}{E *  4 *  \pi *  r^2}

substituting values

            \epsilon  =  \frac{70 *10^{-9}}{2500 *  4 *  3.142 *  (0.16)^2}

            \epsilon  = 8.703 *10^{-11}

7 0
3 years ago
This is what causes acceleration when two forces are acting opposite from each other
Anarel [89]

Answer:

Unbalanced forces is the correct answer.

Explanation:

5 0
3 years ago
(Plzzzz help!!!) (50 points!!!)
stellarik [79]

Answer:

Write the following Quantitiesin scientific notation.

a. 10130 Pa to 2 decimal place

b. 978.15m * s-2 to one decimal place

c 0.000001256 A to3 decimal place​

Add your answer and earn points.

Answer

5.0/5

2

kobenhavn

Expert

5.5K answers

43M people helped

Answer: a.

b.  

c.  

Explanation:

Scientific notation is defined as the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example : 5000 is written as

a. 10130 Pa to 2 decimal place is written as

b.  to 1 decimal place is written as

c.   to 3 decimal places is written as

Explanation:

4 0
2 years ago
Read 2 more answers
3) A 15.0kg cannonball is ascending after being launched. Neglect drag.
WINSTONCH [101]

Answer:

c

Explanation:

3 0
3 years ago
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