Answer:
When oil and water are combined, they do not mix evenly, but instead form two separate layers.
Explanation:
By definition, a pure substance or a homogeneous mixture consists of a single phase. A heterogeneous mixture consists of two or more phases. When oil and water are combined, they do not mix evenly, but instead form two separate layers.
Answer:
F = 75[J]
Explanation:
We know that work is defined as the product of force by distance.
In this way we have two forces, the weight of the block down, and the force that bring about the block to rise.
![W = -(F_{weight*d})+(F_{upward}*d)](https://tex.z-dn.net/?f=W%20%3D%20-%28F_%7Bweight%2Ad%7D%29%2B%28F_%7Bupward%7D%2Ad%29)
where:
W = work = 50 [J]
d = distance = 2 [m]
Fweight = 50 [N]
Fupward [N]
Now replacing:
![50=-(50*2)+(F_{upward}*2)\\50+100=F_{upward}*2\\F_{upward}=150/2\\F_{upward}=75[J]](https://tex.z-dn.net/?f=50%3D-%2850%2A2%29%2B%28F_%7Bupward%7D%2A2%29%5C%5C50%2B100%3DF_%7Bupward%7D%2A2%5C%5CF_%7Bupward%7D%3D150%2F2%5C%5CF_%7Bupward%7D%3D75%5BJ%5D)
People have many different theories but ancient Ramp Find Deepens Mystery. “Using a sled which carried a stone block and was attached with ropes to these wooden posts, ancient Egyptians were able to pull up the alabaster blocks out of the quarry on very steep slopes of 20 percent or more.”
We're given the velocity at two points, and the time between the mentioned two points.
What we'll be calculating is the average acceleration (not to be confused with instantaneous acceleration).
Given two points, lets call them initial and final, the average acceleration is calculated as:
![a= \frac{v_f-v_0}{t}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7Bv_f-v_0%7D%7Bt%7D)
In which
![v_f](https://tex.z-dn.net/?f=v_f)
is the final velocity (in your problem equal to 1m/s),
![v_0](https://tex.z-dn.net/?f=v_0)
is the initial velocity (in your problem equal to 16 m/s), and
![t](https://tex.z-dn.net/?f=t)
the time between two points (in your problem equal to 2s).
So, we plug-in our known values:
The answer is -7.5m/s^2.