1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klasskru [66]
3 years ago
9

What is the purpose of oil used in a car's engine?

Physics
1 answer:
Hoochie [10]3 years ago
5 0
B) to reduce friction
You might be interested in
If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a
Lilit [14]
If a molecule is found to have four hybrid sp3 then we say that it has a <span>tetrahedral molecular geometry. thsi is the correct term to define this type of molecules. So your option would be C. Hope this is useful</span>
7 0
3 years ago
Read 2 more answers
Sug<br>. To repeat the experiment what is it?<br>​
statuscvo [17]

Answer:

....more foam

Explanation:

7 0
3 years ago
A 10-cm-long spring is attached to theceiling. When a 2.0 kg mass is hung from it,the spring stretches to a length of 15 cm.a.Wh
alekssr [168]

(a) 392 N/m

Hook's law states that:

F=k\Delta x (1)

where

F is the force exerted on the spring

k is the spring constant

\Delta x is the stretching/compression of the spring

In this problem:

- The force exerted on the spring is equal to the weight of the block attached to the spring:

F=mg=(2.0 kg)(9.8 m/s^2)=19.6 N

- The stretching of the spring is

\Delta x=15 cm-10 cm=5 cm=0.05 m

Solving eq.(1) for k, we find the spring constant:

k=\frac{F}{\Delta x}=\frac{19.6 N}{0.05 m}=392 N/m

(b) 17.5 cm

If a block of m = 3.0 kg is attached to the spring, the new force applied is

F=mg=(3.0 kg)(9.8 m/s^2)=29.4 N

And so, the stretch of the spring is

\Delta x=\frac{F}{k}=\frac{29.4 N}{392 N/m}=0.075 m=7.5 cm

And since the initial lenght of the spring is

x_0 = 10 cm

The final length will be

x_f = x_0 +\Delta x=10 cm+7.5 cm=17.5 cm

8 0
4 years ago
Read 2 more answers
If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

F= force of attraction

q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0
3 years ago
Resisting force is
Alina [70]

Answer:

D

Explanation:

6 0
3 years ago
Other questions:
  • Which of Newton's Laws explains why satellites need very little fuel to stay in orbit?
    6·1 answer
  • A boat is floating in a small pond. the boat then sinks so that it is completely submerged. what happens to the level of the pon
    7·1 answer
  • A horse was grazing at the top of a small hill. The horse got thirsty and ran toward a
    14·1 answer
  • Can you correctly identify facts about these two historical models of the solar system?
    9·1 answer
  • Match each item to its best description.
    6·2 answers
  • How did Einstein’s and Newton’s theories differ in terms of explaining the cause of gravity?
    15·2 answers
  • What is a coil of wire with a current running running through it
    5·1 answer
  • By experiment, determine what makes a force attractive or repulsive. Describe your experiments and observations with some exampl
    5·1 answer
  • Select all the correct answers.
    10·2 answers
  • How could you improve your boat design to increase the buoyant force without using more clay?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!