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Bas_tet [7]
3 years ago
12

planets A & B are near each other but there is a large difference in their temperatures using the data in the table explain

how the atmosphere of these two planets can influence the average temperature​

Physics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer: Planet A is closer to the Sun and has much greater atmospheric pressure. This suggests that planet A has a thicker atmosphere. Planet A's atmosphere is also mostly made of carbon dioxide, which is a greenhouse gas. This gas retains heat, raising the surface temperature of planet A.

Explanation:

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A speed boat increases its speed uniformly from vi = 20.0 m/s to vf = 30.0 m/s in a distance of 2.00 x 10^2m. (a) Draw a coordin
pychu [463]

a) See graph in attachment

b) The suvat equation to use is v_f^2 - v_i^2 = 2as

c) The acceleration is a=\frac{v_f^2-v_i^2}{2s}

d) The acceleration is 1.25 m/s^2

e) The time needed is 8 s

Explanation:

a)

For this part, find in attachment the diagram representing this situation.

Since we are not given any particular direction for the motion, we choose the x-direction as the direction of motion of the boat.

Then we have the following:

- The initial position of the boat is x_i = 0, the origin

- The  final position of the boat is x_f = 200 m

- The initial velocity of the boat is v_i = 20.0 m/s

- The final velocity of the boat is v_f = 30.0 m/s

Note that the arrow representing the final velocity is longer than that of the initial velocity, since the final velocity is larger.

b)

The motion of the speed boat is a uniformly accelerated motion (motion at constant acceleration), therefore we can use one of the suvat equations. In this particular problem, we know the following quantities:

v_i = 20.0 m/s, the initial velocity

v_f = 30.0 m/s, the final velocity

s = x_f - x_i = 200 m, the  displacement of the boat

Therefore, the equation that best can be use to find the acceleration is

v_f^2 - v_i^2 = 2as

where

a is the acceleration

c)

Now we have to solve the equation

v_f^2 - v_i^2 = 2as

In order to find the acceleration.

This can be done by dividing both terms by 2s: this way, we find

\frac{v_f^2-v_i^2}{2s}=\frac{2as}{2s}

And so the acceleration is

a=\frac{v_f^2-v_i^2}{2s}

d)

Now we can use the equation found in part c) in order to find the acceleration.

We have the following data:

v_i = 20.0 m/s, the initial velocity

v_f = 30.0 m/s, the final velocity

s = x_f - x_i = 200 m, the  displacement of the boat

And substituting into the equation,

a=\frac{30^2-20^2}{2(200)}=1.25 m/s^2

e)

In order to find the time it takes the boat to travel the given distance, we can use the following suvat equation:

v_f = v_i + at

where:

v_i is the initial velocity

v_f is the final velocity

a is the acceleration

t is the time

Here we have:

v_i = 20.0 m/s

v_f = 30.0 m/s

a=1.25 m/s^2

Solving for t, we find:

t=\frac{v_f-v_i}{a}=\frac{30-20}{1.25}=8 s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

8 0
3 years ago
Which of Kepler's laws helps you compare the velocities of different planets?
Rasek [7]

see this and you

try to understand

5 0
3 years ago
What is the correct answer?
damaskus [11]

Answer:

96 million of dollars

Explanation:

p=-6x^3+72x

p=-6(2)^3+72(2)

p=-6(8)+144

p=-48+144

p=96

8 0
3 years ago
4. How often does the sun's magnetic field reverse?
miv72 [106K]
Answer: Every 11 years
3 0
3 years ago
Read 2 more answers
What is the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b?
xeze [42]

The energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

<h3>Change in energy level of the electron</h3>

When photons jump from a higher energy level to a lower level, they emit or radiate energy.

The change in energy level of the electrons is calculated as follows;

ΔE = Eb - Ef

ΔE = -2.68 eV - (-5.74 eV)

ΔE = 3.06 eV

Thus, the energy of the photon emitted when an electron in a mercury atom drops from energy level f to energy level b is 3.06 eV.

Learn more about energy level here: brainly.com/question/14287666

#SPJ1

7 0
2 years ago
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