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3 years ago

what issues might arise in determining the latent heat of something that sublimes in comparison to something that melts

2 answers:

6 0

The heat of sublimation actually has two components, the heat of solidification (actually melting, since this is going in the reverse direction) and the heat of vaporization since you are transforming the solid to a gas. The energy required is the same, even though you do not actually go through a macroscopic melting phase. So the sublimation energy will be much greater than the heat needed for just melting, given the same mass.

Hope this helps!!

vfiekz [6]3 years ago

5 0

Answer:

Sublimation is defined as the direct transition of a substance from solid state to gaseous state. The latent heat of sublimation is the sum of heat required for conversion from solid to liquid and heat required for conversion from liquid to gas. As in sublimation solid substance directly goes to gaseous state therefore, it is very difficult to find the components of latent heat of sublimation. This is the issue which arises in determining latent heat of sublimation.

On the other hand, when substance is melted it physically goes from solid to liquid. One can easily measure the heat required for this conversion.

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A 12.70 g bullet has a muzzle velocity (at the moment it leaves the end of a firearm) of 430 m/s when rifle with a weight of 25.

Norma-Jean [14]

Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

$0=m_{bullet}*v_{bullet} + m_{rifle}*v_{rifle} \\$

assume the bullet goes to right side and the gravitational acceleration =10 $ms^{-2}$

so now the weight of the rifle= $\frac{25}{10}$

$0=m_{bullet}*v_{bullet} + m_{rifle}*v_{rifle} \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}$

this is a negative velocity to the right side. that means the rifle recoils to the left side

3 0

3 years ago

Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m

Reil [10]

Answer:

$\Delta l=0.015m$

Explanation:

We have given initial length of the steel guitar l = 1 m

Cross sectional area $A=0.5mm^2=0.5\times 10^{-6}m^2$

Young's modulus $\gamma=2\times 10^{11}Pa$

Force F = 1500 N

So stress $=\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa$

We know that young's modulus $=\frac{stress}{strain}$

So $2\times 10^{11}=\frac{3\times 10^{9}}{strain}$

$strain=1.5\times 10^{-2}=0.015m$

Now strain $=\frac{\Delta l}{l}$

$0.015=\frac{\Delta l}{1}$

$\Delta l=0.015m$

6 0

3 years ago

Read 2 more answers

2 * 1.5 * (.850/2)^2A small ball with mass 1.50 kg is mounted on one end of a rod 0.850 m long and of negligible mass. The syste

grin007 [14]

Answer

given,

mass of the rod = 1.50 Kg

length of rod = 0.85 m

rotational velocity = 5060 rev/min

now calculating the rotational inertia of the system.

$I = m L^2$

where L is the length of road, we will take whole length of rod because mass is at the end of it.

$I = 1.5 \times 0.85^2$

I = 1.084 kg.m²

hence, the rotational inertia the system is equal to I = 1.084 kg.m²

8 0

3 years ago

You breathe in more oxygen than you breathe out. And you breathe out more carbon dioxide than you breathe in.

AlladinOne [14]

Answer:

B. chemical only.

Explanation:

In the process of respiration which is a chemical process where organic compound is released. In this process exergonic reaction takes place in which compound changes into different ones.

Following are the two types of respiration:-

1] Aerobic respiration:- In this type of respiration requirement of oxygen is more and energy released is more.

2] Anaerobic respiration:- In this type of respiration oxygen requirement is less and energy released is also less.

3 0

3 years ago

A 31.7 kg kid initially at rest slides down a frictionless water slide at 53.2 degrees, how fast is she moving in 3.45 s later?

Murrr4er [49]

Answer:

34.55 m/s

Explanation:

8 0

2 years ago