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Vladimir [108]
3 years ago
7

what issues might arise in determining the latent heat of something that sublimes in comparison to something that melts

Physics
2 answers:
NISA [10]3 years ago
6 0

The heat of sublimation actually has two components, the heat of solidification (actually melting, since this is going in the reverse direction) and the heat of vaporization since you are transforming the solid to a gas. The energy required is the same, even though you do not actually go through a macroscopic melting phase. So the sublimation energy will be much greater than the heat needed for just melting, given the same mass.

Hope this helps!!

vfiekz [6]3 years ago
5 0

Answer:

Sublimation is defined as the direct transition of a substance from solid state to gaseous state. The latent heat of sublimation is the sum of heat required for conversion from solid to liquid and heat required for conversion from liquid to gas. As in sublimation solid substance directly goes to gaseous state therefore, it is very difficult to find the components of latent heat of sublimation. This is the issue which arises in determining latent heat of sublimation.

On the other hand, when substance is melted it physically goes from solid to liquid. One can easily measure the heat required for this conversion.

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A charge q1 of -5.00 x 10^-9 C and a charge q2 of -2.00x 10^-9 C are separated by a distance of 40.0 cm. Find the equilibrium po
aleksandrvk [35]

Answer:

Explanation:

Let the equilibrium position of third charge be x distance from q₁.

Force on third charge due to q₁

= 9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x²

Force on third charge due to q₂

= 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

Both the force will act in opposite direction and for balancing , they should be equal.

9 x 10⁹ x 5 x 10⁻⁹ x 15 x 10⁺⁹ / x² = 9 x 10⁹ x 2 x 10⁻⁹ x 15 x 10⁺⁹ /( .40-x)²

5  / x² = 2 / ( .4 - x )²

Taking square root on both sides

2.236 / x = 1.414 / .4 - x

2.236 ( .4 - x ) = 1.414 x

.8944 - 2.236 x = 1.414 x

.8944 = 3.65 x

x = .245 m

24.5 cm

So the third charge should be at a distance of 24.5 cm from q₁ .

4 0
3 years ago
Merton’s strain theory would have the most trouble explaining which crime?
Ronch [10]
Strain theory would least apply to assault. Strain theory represents the result of society pressuring individuals to conform or to achieve accepted goals. When these goals, such as not making enough money or not being well known, fraud, robbery, and burglaries will take place to counteract it. Assault, on the other hand, is used as a bridge into crimes such as fraud, robbery, or burglary.
5 0
3 years ago
A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
To overcome the problems that blur images and don't provide the best resolution from Earth, astronomers have started using flexi
schepotkina [342]

Answer:

adaptive optics

Explanation:

simple

3 0
3 years ago
I need help ASAP. This is for 15 points
kramer

Answer:

Latitude :

runs: east to west

measures : distances north and south of the equator

Longitude :

runs : north to south

measures : the distance east or west of the Prime Meridian

7 0
3 years ago
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