3s2–4s+5=0 what type of solutions does the equation have? one real solution two real solutions two complex (non-real) solutions
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Answer:
The length of the diagonal support is 69 feet.
Step-by-step explanation:
Dimensions of the box: length = 6 feet
width = 5 feet
height = 8 feet
The diagonal support relates with the diagonal of the base and the height.
From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;
=
+
=
+
= 36 + 25
= 61
x =
= 7.81
let the length of the diagonal support be represented by l. So that;
=
+
=
+
= + 64
l =
= 61 + 8
= 69
Thus, the length of the diagonal support is 69 feet.
Answer:
The ball will hit the ground at 10 seconds and its maximum height is 1024 feet.
Step-by-step explanation:
Height of a mountain, h = 90 feet
Upward velocity of a ball, u = 64 ft/s
Its height as a function of time can be written by using the second equation of motion as follows :
.....(1)
When it will hit the ground, f(x) = 0
It is quadratic equation.
t = -6 s and t = 10 s
Neglecting -6 seconds, the ball will hit the ground at 10 seconds.
For maximum height,
Put f'(x) = 0
Put t = 2 in equation (1)
Hence, the ball will hit the ground at 10 seconds and its maximum height is 1024 feet.