The change is that the water will freeze to 0 or minus I don’t know as I’m not to sure
Which of the factors that influence decision making would likely give you the most trouble? What can you do to position this factor more in your favor?
Answer:
38825.472 M
Explanation:
Using
C1V1=C2V2
To make solution B,
C1 = 25.527 M, V1 = 13 mL
C2 = 25.527 x 8 = 204.216 M
V2 = 13 X 12 = 156 mL
To make solution C'
C1 = 8 X 202.216 M = 1617.728
V1 = 8 X 156mL = 1248 mL
V2 = 4 X 13 = 52 mL
C2 = C1V1 / V2
=1617.728 X 1248 / 52
=38825.472 M
Answer:
Freezing T° of solution = - 4.52°C
Explanation:
ΔT = Kf . m . i
That's the formula for colligative property about freezing point depression.
Li₂O is an oxide that can not be dissociated but, if we see it's a ionic compound.
Li₂O → 2Li⁺ + O⁻²
3 moles of ions have been formed. Ions dissolved in solution are i, what we call Van't Hoff factor.
m is molality → 0.811 m, this is data
Kf →Cryoscopic constant, for water is 1.86 °C/m
and ΔT = Freezing T° of pure solvent - Freezing T° of solution
We replace: 0°C - Freezing T° of solution = 1.86°C/m . 0.811 m . 3
Freezing T° of solution = - 4.52°C
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