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gregori [183]
3 years ago
11

Explain the difference between an organic and inorganic compound.

Chemistry
2 answers:
galben [10]3 years ago
8 0
The most common differentiation to help distinguish between organic and inorganic compounds used to be the fact that organic compounds result from the activity of living beings, whereas inorganic compounds are either the result of natural processes unrelated to any life form or the result of human experimentation in the laboratory.<span><span /></span>
Brut [27]3 years ago
5 0
Organic compounds are all natural and are from nature whereas non organic compounds are made by people in a lab
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Year/ Distance (cm)
luda_lava [24]

Answer:

the answer is C

Explanation:

6.7 to 13.2 then look at the numbers they go up but not a lot each time

5 0
3 years ago
What are a physical properties?
pychu [463]
Physical properties include: appearance, texture, color, boiling point, melting point, ect.
7 0
3 years ago
What mass of Hg will occupy a volume of 75.0 mL?
k0ka [10]
75.0 mL in liters:

75.0 / 1000 => 0.075 L

1 mole -------------------- 22.4 L ( at STP)
( moles Hg) ------------- 0.075 L

moles Hg = 0.075 x 1 / 22.4

moles = 0.075 / 22.4

= 0.00334 moles of Hg

Hg => 200.59 u

1 mole Hg ----------------- 200.59 g
<span>0.00334 moles Hg ----- ( mass Hg )
</span>
mass Hg = 200.59 x 0.00334 / 1

mass Hg = 0.6699 / 1

= 0.6699 g of Hg




7 0
3 years ago
Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m
erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3}  =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2}  =0.06882molBr^-

Now, we compute the total moles of bromide:

n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol

Then, the total volume in liters:

150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L

Therefore, the concentration of total bromide is:

M=\frac{0.12338mol}{0.325L}\\\\M=0.380M

Best regards!

8 0
2 years ago
What are the reactants and products? Write a reaction equation and label the reactants and products.
djyliett [7]
Reactants are the substance that undergo a change in a chemical reaction while products are what is produced after a reaction. don't have time to write a reaction.
8 0
3 years ago
Read 2 more answers
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