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4 years ago

Explain whether your breakfast was a compound, homogeneous mixture, or heterogenous mixture.

Chemistry

1 answer:

leonid [27]4 years ago

7 0

what did you eat for breakfast?

I can't help you otherwise

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In the formula shown, what is the total number of atoms present?

patriot [66]

Answer:

your answer

24. hope helpful answer

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3 years ago

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What is a chemical test to distinguish between the liquids hexane and hexene

WINSTONCH [101]

Hexane is alkane and hexene is alkene.

They can be distinguish by bromine test.

Hexane being a saturated hydrocarbon does not decolourizes Br2 in CCl4 and hexene being unsaturated decolourizes Br2 in CCl4.

Reaction : CH3CH2CH2CH2CH2=CH2 + Br2 in CCl4 ------> CH3CH2CH2CH2CH2(Br)CH2Br ( colourless)

Read more on Brainly.in - https://brainly.in/question/2820606#readmore

6 0

4 years ago

Plz help as soon as you can

Nesterboy [21]

Answer:

98.08 g/mol

Explanation:

Hope this helps.

7 0

3 years ago

Which one of the following elements is stable?

Goshia [24]

Group 18 are stable because thier outermost shell ocuppied with full of electrons and its chemically inert

3 0

3 years ago

What is per cent by mass of Na2CO3 in a 1.0 molal aqueous solution ?

aivan3 [116]

Hello!

We have the following data:

MM (Molar mass of Na2CO3)
Na = 2*23 = 46 u
C = 1*12 = 12 u
O = 3*16 = 48 u
----------------------
MM (Molar mass of Na2CO3) = 46+12+48 = 106 g/mol
n (mol number) = 1 mol
m1 (mass of the solute) = ?

$n = \dfrac{m_1}{MM}$

$1\:mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}= \dfrac{m}{106\:g/mol\!\!\!\!\!\!\!\!\!\!\!\dfrac{\hspace{0.6cm}}{~}}$

$m_1 = 1*106$

$\boxed{m_1 = 106\:g}\Longleftarrow(solute\:mass)$

So if we have the dissolution in a liter (m2 - mass of solvent), that is 1000g , then the total mass of the solution (m) will be:

$m\:(solution\:mass) = m_1\:(solute\:mass) + m_2\:(solvent\:mass)$

$m = 106\:g+1000\:g$

$\boxed{m = 1106\:g}\Longleftarrow(solution\:mass)$

<span>Now, let's find the percentage in mass (% m / m), let's see:
</span>
$\%(m/m) = \dfrac{m_1}{m}*100$

$\%(m/m) = \dfrac{106}{1106}*100$

$\%(m/m) = \dfrac{10600}{1106}$

$\%(m/m) = 9.58408...\to\:\boxed{\boxed{\%(m/m) \approx 9.6}}\end{array}}\qquad\checkmark$

Answer: B) 9.6

I Hope this helps, greetings ... DexteR!

5 0

3 years ago