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EastWind [94]
3 years ago
14

For the chemical reaction

Chemistry
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

806.3g

Explanation:

Given parameters:

 Number of moles of silver nitrate  = 4.85mol

Unknown:

Mass of silver chromate = ?

Solution:

         2AgNO₃ + Na₂CrO₄  →  Ag₂CrO₄ + 2NaNO₃

To solve this problem, we work from the known to the unknown;

  • The known specie here is  AgNO₃ ;

   From the balanced chemical equation;

          2 moles of AgNO₃  will produce 1 mole of Ag₂CrO₄

          4.85 moles of AgNO₃  will produce \frac{4.85}{2}   = 2.43moles of Ag₂CrO₄

  • Mass of silver chromate produced;

        mass = number of moles x molar mass

   Molar mass of  Ag₂CrO₄

    Atomic mass of Ag = 107.9g/mol

                                 Cr  = 52g/mol

                                  O  = 16g/mol

  Input the parameters and solve;

     Molar mass  = 2(107.9) + 52 + 4(16) = 331.8g/mol

  So,

        Mass of Ag₂CrO₄ = 2.43 x 331.8 = 806.3g

     

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