A gas that occupies 4.31 litres at a pressure of 0.755 atm will have a temperature of 39.58°C. Details about temperature can be found below.
<h3>How to calculate temperature?</h3>
The temperature of a gas can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
0.755 × 4.31 = 1 × 0.0821 × T
3.25 = 0.0821T
T = 3.25 ÷ 0.0821
T = 39.58°C
Therefore, a gas that occupies 4.31 litres at a pressure of 0.755 atm will have a temperature of 39.58°C.
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Answer:
![[N_2]=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3D0.0866M)
Explanation:
Hello there!
In this case, in agreement to the chemical reaction, it is possible for us to figure out the equilibrium concentration of the N2 product, via an ICE table plugged in the equilibrium expression:
![Kc=\frac{[N_2][O_2]}{[NO]^2}\\\\2.4x10^3=\frac{x*x}{(0.175-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%5C%5C%5C%5C2.4x10%5E3%3D%5Cfrac%7Bx%2Ax%7D%7B%280.175-2x%29%5E2%7D)
In such a way, when solving for x via quadratic equation or just a solver, it is possible to obtain:

In such a way, since the root 0.0884 M produce a negative concentration of NO (0.175-2*0.0884=-0.0018M), we infer that the correct root is 0.0866 M; therefore, the concentration of N2 at equilibrium is equal to x:
![[N_2]=x=0.0866M](https://tex.z-dn.net/?f=%5BN_2%5D%3Dx%3D0.0866M)
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Answer: Star formation begins when the denser parts of the cloud core collapse under their own weight/gravity. These cores typically have masses around 104 solar masses in the form of gas and dust. The cores are denser than the outer cloud, so they collapse first.
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