Answer:
The mass of 1.00 mol of allicin, rounded to the nearest integer, is 162 g
Explanation:
Allicin is a compound that derivates from the alliin which is produced by the catalyzis of an enzime.
The molecular formula is: C₆H₁₀OS₂.
Let's determine the molar mass which is the mass that corresponds to 1 mol
Molar mass C . 6 + Molar mass H . 10 + Molar mass O + Molar mass S . 2 =
12 g/mol . 6 + 1 g/mol . 10 + 16 g/mol + 32.06 g/mol . 2 = 162.1 g/mol
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The numerical value of Kc is 1.129 x10^4
<u><em> Explanation</em></u>
C3H6O +4O2→ 3 CO2 + 3H2O
KC is the ratio of concentration of the product over the reactant.
Each concentration of product and reactant are raised to the power of its coefficient.
Therefore the KC expression of equation above is
Kc=[ (Co2)^3 (H2O)^3] / [(C3H6O) (O2)^4)]
Kc =[(1.8^3) x (2.0^3)] / [(0.51) x (0.30^4)] =1.129 x10^4
The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.
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