Answer:
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Answer:
0.246 kg
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>
<em />
We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:
0.3700 L × 2.25 mol/L = 0.833 mol
The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:
0.833 mol × 295.56 g/mol = 246 g
1 kilogram is equal to 1000 grams. Then,
246 g × (1 kg/1000 g) = 0.246 kg
H-Cl pair of atoms has the most polar bond.
Charles's Law.
<u>V1</u><u> </u> = <u>V2</u>
T1 T2
V1 = 720 mL
T1 = 22°C
T2 = 106°C
V2 = ?
then,
<u>7</u><u>2</u><u>0</u><u> </u> = <u>V2</u><u> </u>
22 106
V2 = 3469 mL
