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bezimeni [28]
3 years ago
11

To perform a certain type of blood analysis, lab technicians must perform two procedures. The first procedure requires either on

e or two separate steps, and the second procedure requires either one, two, or three steps. a. How many experimental outcomes exist for the blood analysis experiment?
Chemistry
1 answer:
kirza4 [7]3 years ago
7 0

Answer: There are 6 different outcomes.

Explanation:

There are two options for procedure one (one or two steps) and three options for procedure two (one, two or three steps). If we multiply those options , the result is the total number of outcomes for the analysis.

2 x 3 = 6

These being

- One step on procedure one and one step on procedure two

- One step on procedure one and two steps on procedure two

- One step on procedure one and three steps on procedure two

- Two steps on procedure one and one step on procedure two

- Two steps on procedure one and two steps on procedure two

- Two steps on procedure one and two steps on procedure two

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velikii [3]

Answer:

yes

Explanation:

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3 years ago
What is the density of a block of marble that occupies 277 cm3 and has a mass of 928 g? Answer in units of g/cm3 .
Evgesh-ka [11]
V=277cm^{3}\\
m=928g\\\\
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3 years ago
How many moles are in 7.2x10^15 atoms of Pb?​
fiasKO [112]
<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

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