Answer: E) Acceleration, net force
Explanation: In order to explain this problem we have to consirer that the uniform circulat motion has constant angular velocity (ω) and the vector velocity is changed its direction for any point that cover the circle but its modulus is contant and its value is v=ω*R. In order to ensure these conditions, the net force also the accelaration called centripetal must point to the center of the circular trajectory.
Answer:
c is the right answer is it
Answer:
a = 3.27 m/s²
F = 32.7 N
Explanation:
Draw a free body diagram. There are three forces:
Weight force mg pulling straight down.
Normal force N pushing perpendicular to the slope.
Friction force F pushing parallel up the slope.
Sum of forces in the parallel direction:
∑F = ma
mg sin θ − F = ma
Sum of torques about the cylinder's axis:
∑τ = Iα
Fr = ½ mr²α
F = ½ mrα
Since the cylinder rolls without slipping, a = αr. Substituting:
F = ½ ma
Two equations, two unknowns (a and F). Substituting the second equation into the first:
mg sin θ − ½ ma = ma
Multiply both sides by 2/m:
2g sin θ − a = 2a
Solve for a:
2g sin θ = 3a
a = ⅔ g sin θ
a = ⅔ (9.8 m/s²) (sin 30°)
a = 3.27 m/s²
Solving for F:
F = ½ ma
F = ½ (20 kg) (3.27 m/s²)
F = 32.7 N
The most likely answer will be B. Overfishing is still a large issue today, and it can really ruin a habitat. =)