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madam [21]
4 years ago
10

(05.02 LC)

Mathematics
2 answers:
Kisachek [45]4 years ago
8 0

Answer:

y=-4x

Step-by-step explanation:

WE need to write the equation for the given graph

In the graph y intercept is (0,0)

The equation of linear graph is y=mx+b

where m is the slope and b is the y intercept

From the given graph y intercept is 0 so b=0

to find slope pick two points from the graph

(0,0) and (1, -4)

slope = \frac{y_2-y_1}{x_2-x_1} = \frac{-4-0}{1-0} = -4

m=-4  and b=0

So the equation becomes

y= -4x+0

y= -4x

riadik2000 [5.3K]4 years ago
5 0
Y= - 4x, does that help you in your flvs exam??
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Plz answer hurry. 20 points for right answer
lapo4ka [179]
Did You Figure This Out I Need Help Too. Lol
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3 years ago
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Tony has a rectangular yard he would like to fence. He knows the length of his yard is 3x3+4x2−6x and the width of the yard is 2
Step2247 [10]

Answer:

P = 6x³ + 12x² - 18x + 8

Step-by-step explanation:

Given that:

Length = 3x3+4x2−6x

Width = 2x2−3x+4

The length of fencing needed will be :

Perimeter of rectangle (P) = 2( Length + Width)

P = 2[ (3x3+4x2−6x) + (2x2−3x+4)]

P = 2 (3x³+ (4x² + 2x²) + (-6x - 3x) + 4)

P = 2(3x³ + 6x² - 9x + 4)

P = 6x³ + 12x² - 18x + 8

6 0
3 years ago
Please HELP!<br> How do I factorise 2x^2 - 11x -6x <br> please include working <br> Thanks!
Harrizon [31]

Answer:

x(2x-17)

Step-by-step explanation:

2x^2 -11x-6x

2x^2-17x

x is common

x(2x-17)


6 0
3 years ago
Read 2 more answers
A simple random sample with n = 58 provided a sample mean of 24.5 and a sample standard deviation of 4.4. (Round your answers to
nasty-shy [4]

Answer: (23.53, 25.47)

Step-by-step explanation:

The confidence interval for population mean(when population standard deviation is unknown) is given by :-

\overline{x} \pm\ t^*\dfrac{s}{\sqrt{n}}

, where \overline{x} = sample mean

n = sample size.

s = sample standard deviation.

t* = Critical value.

Given : \overline{x}=24.5

s= 4.4

Confidence level = 90% =0.090

Significance level = \alpha=1-0.90=0.10

Sample size : n= 58

Degree of freedom : df= n-1= 57

Using t-distribution table , the critical value :

t_{\alpha/2,\ df}= t_{0.05,\ 57}=1.6720

Then, the confidence interval will be :-

24.5 \pm\ (1.6720)\dfrac{4.4}{\sqrt{58}}

24.5 \pm\ (1.6720)\dfrac{4.4}{7.61577310586}

24.5 \pm\ 0.965995165263\approx24.5\pm0.97\\\\=(24.5-0.97,\ 24.5+0.97)\\\\=(23.53,\ 25.47)

Hence, a 90% confidence interval for the population mean = (23.53, 25.47)

6 0
4 years ago
An alrcraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on
rewona [7]

C(x) should be ;

C(x)=0.9x² - 306x +36,001

Answer:

$9991

Step-by-step explanation:

Given :

C(x)=0.9x^2 - 306x +36,001

To obtain minimum cost :

Cost is minimum when, C'(x) = 0

C'(x) = 2(0.9x) - 306 = 0

C'(x) = 1.8x - 306 = 0

1.8x - 306 = 0

1.8x = 306

x = 306 / 1.8

x = 170

Hence, put x = 170 in C(x)=0.9x²- 306x +36,001 to obtain the

C(170) = 0.9(170^2) - 306(170) + 36001

C(170) = 26010 - 52020 + 36001

= 9991

Minimum unit cost = 9991

5 0
3 years ago
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