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Natasha2012 [34]
3 years ago
15

4. Determine whether the statement is true or false. Prove the statement directly from the definition if it is true, and give a

counterexample if it is false. The average of two odd integers is odd.
Mathematics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

The statement is false.

Step-by-step explanation:

Let a and b represent two odd integers.

The average (A) is defined by:

A=\frac{a+b}{2}

In order to prove the statement, you have to show that it's true for all odd integers. But, to disprove it, you just have to find a counterexample where the statement is false.

Notice that it is easier to try to find a counterexample.

For example, a=3 and b=5

A= \frac{3+5}{2} = \frac{8}{2} = 4

The result of the average is even, therefore the statement is false.

The previous calculation is a counterexample.

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a square has a side length of x. A rectangle has a length that is 4 inches longer than the square and a width that is 2 inches s
vodomira [7]

Answer:

Length of the rectangle is = 8 inches.

Step-by-step explanation:

Given :

Area of square = Area of the rectangle

According to the question:

Length of the square be 'x'.

Its area = (Side)*(Side) =x^2   ...equation (i)

Length of the rectangle = (x+4)

Width of the rectangle = (x-2)

Area of the rectangle =Length * Width

⇒(x+4)(x-2)=x^2-2x+4x-8

⇒x^2+2x-8          ...equation  (ii)

Equating both the equation as area of both the figure are equal.

⇒ x^2+2x-8=x^2

⇒ 2x-8=0     ...subtracting x^2 both sides

⇒ 2x=8           ...dividing both sides with 2

⇒ x=\frac{8}{2}=4 inches

Plugging the value of x=4 in the length of the rectangle.

We have,

⇒(x+4)=(4+4)=8

So the length of the rectangle = 8 inches.

4 0
3 years ago
Please help du tomorrow
Leokris [45]
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².

To find the perimeter of each, we add the area of all sides.  For the first figure, the missing sides are 1 cm and 6 cm.  To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.

For the second figure, the missing sides are 4 cm and 3 cm.  To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.

For the third figure, the missing sides are 3 cm, 3 cm and 8 cm.  To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.

For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm.  To find the area, we have two squares whose dimensions are 10x10.

For the fifth figure, the missing sides are 3 cm and 9 cm.  To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
3 0
3 years ago
If I have 60 coins consisting of dimes and quarters and I have x dimes give an expression that would represent the number of qua
Nikolay [14]

Hey there!

Here is an exspression that would help recognize the amount of quarters you have:

X = Dimes

K = Quarters

X + K = 60 coins

Hope this helps!

3 0
3 years ago
Round 24,061,562 to the nearest 1,000 and 100,000
jenyasd209 [6]

Nearest 1,000 = 24,062,000

Nearest 100,000= 24,100,000

Hope its correct :)

6 0
3 years ago
Read 2 more answers
Are the expressions 3+y and 13(6+y) equivalent?
ira [324]

Answer: no because 13(6+y) is 78+ 13y

Step-by-step explanation:

4 0
3 years ago
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