Answer: (a) cesium and bromine :
(b) sulfur and barium: 
(c) calcium and fluorine :
Explanation:
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
The nomenclature of ionic compounds is given by:
1. Positive is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
(a) cesium and bromine: Here cesium is having an oxidation state of +1 called as 
cation and bromine 
is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral 
called as cesium bromide.
(b) sulfur and barium : Here barium is having an oxidation state of +2 called as 
cation and sulphur 
is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral . called as barium sulfide.
(c) calcium and fluorine: Here calcium is having an oxidation state of +2 called as 
cation and fluorine 
is an anion with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral . called as calcium fluoride.
Given:
Volume of KOH = 53.0 mL
Concentration of KOH = 0.320 M
Volume of HNO3 = 28.0 mL
Concentration of HNO3 = 0.250 M
Balanced Equation:
KOH + HNO3 ===> KNO3 + H2O
0.320 0.250 0 0
H2O ===> H+ + OH-
Solve for the concentration of OH-
She should leave 6.41 because 42.76 x 15%
Answer:
1 mole is equal to 1 moles Potassium, or 39.0983 grams.
39.0983g X 4 = 156.3932
so 4 moles are in 156 grams of Potassium
Explanation:
Hope this helps
-A Helping Friend (mark brainliest pls)
