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3 years ago

What is the volume of 62.0 g of ether if the density of ether is 0.56 g/mL?

Chemistry

1 answer:

777dan777 [17]3 years ago

3 0

Answer:

110.71

Explanation:

Density = mass ÷ volume

0.56 g = 62.0 g ÷ Volume

(0.56g ÷ 1 ) cross× (62.0 g ÷ Volume )

Volume = (62.0 g ÷ 0.56)

volume = 110.71

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Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

<u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

<u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

4 years ago

Using this balanced equation: 2 NaOH + H2SO4 —> H2O + Na2SO4

mars1129 [50]

<h3>Answer:</h3>

266.325 g

<h3>Explanation:</h3>

We are given the balanced equation;

2NaOH + H₂SO₄ → H₂O + Na₂SO₄

Mass of NaOH as 150 g

We are required to determine the mass of Na₂SO₄ that will be formed.

<h3>Step 1: Determine the number of moles of NaOH</h3>

Moles = Mass ÷ molar mass

Molar mass of NaOH is 40.0 g/mol

Therefore;

Moles of NaOH = 150 g ÷ 40 g/mol

= 3.75 moles

<h3>Step 2: Determine the number of moles of sodium sulfate formed</h3>

From the equation 2 moles of NaOH reacts with sulfuric acid to form 1 mole of sodium sulfate.
Therefore; mole ratio of NaOH : Na₂SO₄ is 2 : 1

Thus, moles of Na₂SO₄ = Moles of NaOH ÷ 2

= 3.75 moles ÷ 2

= 1.875 moles

<h3>Step 3: Determine the mass of Na₂SO₄ produced.</h3>

we know that;

Mass = Moles × Molar mass

Molar mass of Na₂SO₄ is 142.04 g/mol

Therefore;

Mass of Na₂SO₄ = 1.875 moles × 142.04 g/mol

= 266.325 g

Thus, the mass of sodium sulfate formed 266.325 g

7 0

4 years ago

Which of the elements shown will not form ions, and why will they not do so?

grigory [225]

No elements visible!

Ions form between metals and non-metals.

Hope this helps!

6 0

3 years ago

What is the volume, in Liters, of 0.765 mol of carbon monoxide gas at STP?

aivan3 [116]

Answer:

The volume at STP of 0,765 moles of carbon monoxide gas is 17, 125 L.

Explanation:

We use the ideal gas formula, with the constant R = 0.082 l atm / K mol. The STP conditions are : 1 atm pressure and 273 K temperature. Solve for the formula, V (volume):

PV=nRT ---> V= (nRT)/P

V= (0,765 mol x0,082 l atm/ K mol x 273 K)/ 1 atm

8 0

3 years ago

All atoms of the same element have the same:

Korvikt [17]

They have the same number of protons

8 0

3 years ago

Read 2 more answers