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stiks02 [169]
3 years ago
7

A sample of iodine is easiest to ship as a powder because it is making it easy to break into small pieces.What goes in the blank

?
Chemistry
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Answer:

The correct answer is "brittle".

Explanation:

A sample of iodine is easiest to ship as a powder because it is "brittle", making it easy to break into small pieces. Brittle is a characteristic of substances that are hard and dry, which makes them liable to break or shatter easily. Iodine is a substance that is brittle because in its solid state, the particle experience strong electrostatic attractions, which makes them very volatile.

Gemiola [76]3 years ago
7 0
The answer is brittle 
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What do you think is the primary reason why the Unionid mussel population declined whenever there is a dramatic increase in the
sertanlavr [38]

Answer:

When the Zebra arrived they ate all the food so the Unionid mussels declined as they died from the lack of food. Causing the Zebra Zebra numbers to increase and Unionid numbers to decline.

6 0
2 years ago
Aluminum has a density of 2.70 g/mL. A sample of aluminum weighs 67.5 g. If this sample is put into a graduated cylinder that ha
romanna [79]

Answer:

60 ml

Explanation:

Now, we know that density = mass/volume

Mass of aluminium = 67.5 g

volume of aluminium =?

density of aluminium = 2.70 g/mL

volume of aluminium = mass/density = 67.5/2.70 = 25 ml

Since volume of water in the cylinder = 35 ml

The water rises to ; 35 ml + 25 ml = 60 ml

4 0
2 years ago
What contribution to atomic theory resulted from albert einstein’s work?
gizmo_the_mogwai [7]

Answer: A new model of the atom that described electrons as being in a cloud

Explanation:

7 0
3 years ago
Read 2 more answers
4. How many grams of ammonium carbonate are needed to decompose in order to produce
Thepotemich [5.8K]

Answer:

14.23g of (NH4)2CO3

Explanation:

We'll begin by writing the balanced equation for the reaction.

(NH4)2CO3 –> (NH4)2O + CO2

Next,, we shall determine the mass of (NH4)2CO3 that decomposed and the mass of CO2 produced from the balanced equation. This is illustrated below:

Molar mass of (NH4)2CO3 = 2[14+(4x1)] + 12 + (16x3)

= 2[14 +4] + 12 + 48

= 2[18] + 60 = 96g/mol

Mass of (NH4)2CO3 from the balanced equation = 1 x 96 = 96g

Molar mass of CO2 = 12 + (2x16) = 44g/mol

Mass of CO2 from the balanced equation = 1 x 44 = 44g.

Summary:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Finally, we can determine the mass of (NH4)2CO3 that decomposed to produce 6.52g of CO2 as follow:

From the balanced equation above,

96g of (NH4)2CO3 decomposed to produce 44g of CO2.

Therefore, Xg of (NH4)2CO3 will decompose to produce 6.52g of CO2 i.e

Xg of (NH4)2CO3 = (96 x 6.52)/44

Xg of (NH4)2CO3 = 14.23g

Therefore, 14.23g of (NH4)2CO3 is needed to produce 6.52g of CO2.

4 0
3 years ago
What is the molarity of a solution of 58.7 grams of MgCl2 in 359 ml of solution?
jekas [21]

Answer:

1.72 M

Explanation:

Molarity is the molar concentration of a solution. It can be calculated using the formula a follows:

Molarity = number of moles (n? ÷ volume (V)

According to the information provided in this question, the solution has 58.7 grams of MgCl2 in 359 ml of solution.

Using mole = mass/molar mass

Molar mass of MgCl2 = 24 + 35.5(2)

= 24 + 71

= 95g/mol

mole = 58.7g ÷ 95g/mol

mole = 0.618mol

Volume of solution = 359ml = 359/1000 = 0.359L

Molarity = 0.618mol ÷ 0.359L

Molarity = 1.72 M

6 0
3 years ago
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