3 39/40 = 3.975
3 19/20 = 3.95
3 1/2 = 3.5
least to greatest : 3 1/2, 3 19/20, 3 39/40
Answer:
The answer to your question is car 1 = 30 gal and car 1 = 20 gal
Step-by-step explanation:
car 1 = a
car 2 = b
Efficiency of car 1 = 35 mi/gal
Efficiency for car 2 = 20 mi/gal
Total distance = 1450
Total gas consumption = 50 gal
Equations
35a + 20b = 1450 ------- (I)
a + b = 50 ------- (II)
Solve by elimination
Multiply equation II by -35
35a + 20b = 1450
-35a - 35b = -1750
Simplify
0 - 15b = -300
Solve for b
b = -300/-15
Result
b = 20
Substitute b in equation II to find a
a + 20 = 50
Solve for a
a = 50 -20
Result
a = 30
Answer:
v = 8
Step-by-step explanation:
-10= -5/4v first multiply both sides of the equation by -4/5
-10(-4/5) = v this cancels out the right side.
multiply the left side.
so you are left with 40/5 = v
next, simplify you will get 8=v
I think its 40 over 81, 40/81
