A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
Learn more : brainly.com/question/7619478
Answer:
x > 10/3
x will always be greater that 10/3 never the same nor less.
Step-by-step explanation:
3/5x + 1/3 < 4/5x - 1/3
3/5x - 4/5x + 1/3 < -1/3
-1/5x + 1/3 < -1/3
-1/5x < -1/3 - 1/3
-1/5x < -2/3
-1/5x/-1 < -2/3/-1 (Since it is both divided by a negative the sign switches, the sign also switches with multiplication. *Note: it only switches if it is negative!*)
1/5x > 2/3
5 • 1/5x > 2/3 • 5
x > 2/3 • 5/1
x > 10/3
The vertex is (3,0).
The 3 inside the abs val bar tells you the x value of the vertex is 3. No number outside the abs value bar is a +0 which is the y value of the vertex.
Answer:
20/3 or 6.67 or 6 
(any of these are correct)
Step-by-step explanation:
Volume of triangular pyramid formula is V = 1/3 * base area * height
V = 1/3 * 5 * 4 = 20/3
20/3 or 6.67 or 6
Triangle ABD and ADC are righttriangles so u can use the Pythagorean theorem/triples. the triples are 3/4/5 and 5/12/13. 12 is 4x3, and 15 is 5x3, so BD is 3x3, which is 9. AC is 13, as it is part of the Pythagorean’s triples
