Hi there,
I used the Desmos graphing calculator to graph the point -3≥x-y and this is what i got
Your coordinate points will be (0,3) and (-3,0)
Hope this is correct :)
Have a great day
Find the value of x in the triangle shown below
2 answers:
Answer:
<h2>46.4°</h2>Step-by-step explanation:
Apply sine formula:
Plug the values
Apply cross product property
Hope this helps .....
Best regards!!!
Answer:
x = 46.37 degrees
Step-by-step explanation:
<u><em>Using cosine rule</em></u>
Where a = 5 , b = 6.9 , c = 5 and C = x (Unknown)
In the cosine rule, a and b are the sides containing the angle and c is the opposite side of the angle C
Plugging in the values:
=>
=>
Subtracting 72.61 to both sides
=>
=> -47.61 = -69 Cos x
=> 47.61 = 69 Cos x
Dividing both sides by 69
=> Cos x = 0.69
Multiplying both sides by
=> x =
=> x = 46.37 degrees
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Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that . Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that . In this equality we can perform a right multiplication by
and obtain
. Then, in the obtained equality we perform a left multiplication by P and get
. If we write
and
we have
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and . So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.