Think your answer is $27,100.
It is composite because it can be factored out as 5x3 or 15x1
Answer:
|96.55−0.02|= x
|96.55+0.02|=x
Step-by-step explanation:
Given that:
Measured length of beam = 96.55 cm
Measurement accuracy = plus or minus (± 0.02cm)
Limits of actual length of the beam:
Let limit of actual length = x
Lower limit :
|measured length - accuracy| = x
|96.55 - 0.02| = x
96.53) x
Upper limit :
|measured length + accuracy| = x
|96.55 + 0.02| = x
96.57 = x
Answer:
<h2>
![x = - \frac{19}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B19%7D%7B4%7D%20)
</h2>
Option B is the correct option.
Step-by-step explanation:
![- \frac{1}{2} + x = - \frac{21}{4}](https://tex.z-dn.net/?f=%20-%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20x%20%3D%20%20-%20%20%5Cfrac%7B21%7D%7B4%7D%20)
Move constant to R.H.S and change its sign:
![x = - \frac{21}{4} + \frac{1}{2}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B21%7D%7B4%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20)
Take the L.C.M
![x = \frac{ - 21 + 1 \times 2}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%2021%20%2B%201%20%20%5Ctimes%202%7D%7B4%7D%20)
![x = \frac{ - 21 + 2}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B%20-%2021%20%2B%202%7D%7B4%7D%20)
Calculate
![x = - \frac{19}{4}](https://tex.z-dn.net/?f=x%20%3D%20%20-%20%20%5Cfrac%7B19%7D%7B4%7D%20)
Hope this helps...
Good luck on your assignment..
Umm I’m not good at showing my work but the answer is -1.21