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4 years ago

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A 24.81g sample of a gaseous compound containing only oxygen,and chlorine is determined to contain 3.01g carbon, 4.00g oxygen an

d 17.81g chlorine .what is this compound's percent composition?

1 answer:

irinina [24]4 years ago

3 0

Answer:

hi

Explanation:

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Given the formula representing a compound: What is the IUPAC name of this compound?

Drupady [299]

Answer:

2,2- dichloro-heptane

Explanation:

The IUPAC name of the compound is 2,2-dichloro-heptane

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3 years ago

What color has a wavelength of 6.49*10^23?

Yakvenalex [24]

Wavelength of any wave can't be equal to the number with exponential of 23, otherwise, if you're focusing on visible light, and neglecting the exponential then your color would be: orange. [ Again, remember wavelengths can be in between 10 to 10^-14 ]

In short, Your Answer would be: Orange

Hope this helps!

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3 years ago

Read 2 more answers

Worksheet Ch.3: % Composition, Molarity, and Other Units for

Ann [662]

The percentage composition by mass of the elements in the compound are:

Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%

Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%

Bi. The percentage composition by mass of Zinc in the compound is 67.1%

Bii. The percentage composition by mass of Sulfur in the compound is 32.9%

Percentage composition by mass of an element in a compound can be obtained by using the following formula: $Percentage = \frac{mass of Element}{mass of compound} * 100$

Ai. Determination of the percentage of Na in 3.65 g of NaF

Mass of Na = 2 g

Mass of NaF = 3.65 g

<h3>Percentage of Na =? </h3>

$Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100$

<h3>Percentage of Na = 54.8%</h3>

Aii. Determination of the percentage of F in 3.65 g of NaF

Mass of F = 1.65 g

Mass of NaF = 3.65 g

<h3>Percentage of F =? </h3>

$Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\$

<h3>Percentage of F = 45.2%</h3>

Bi. Determination of the percentage composition of Zn in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

<h3>Percentage of Zn =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\$

<h3>Percentage of Zn = 67.1%</h3>

Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound

Mass of Zn = 32.69 g

Mass of compound = 48.72 g

Mass of S = 48.72 – 32.69 g

Mass of S = 16.03 g

<h3>Percentage of S =? </h3>

$Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of S = \frac{16.03}{48.72} * 100\\\\$

<h3>Percentage of S = 32.9%</h3>

Learn more: brainly.com/question/1350382

3 0

3 years ago

A plant uses the energy from sunlight to create oxygen and glucose from carbon dioxide and water. Which statement is true about

Roman55 [17]

Answer:d

Explanation:so it can grow

7 0

3 years ago

larisa [96]

Answer:

group I: alkali metals

group II (beryllium to radium): alkaline earth metals

group II (scandium to zinc , yttrium to cadmium, lanthanoid series to mercury, actinoid series to copernicium): transition metals

group VII (fluorine to astatine): halogens

group VIII: (helium to radon): noble gases

Explanation:

3 0

3 years ago