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sineoko [7]
3 years ago
14

A 24.81g sample of a gaseous compound containing only oxygen,and chlorine is determined to contain 3.01g carbon, 4.00g oxygen an

d 17.81g chlorine .what is this compound's percent composition?​
Chemistry
1 answer:
irinina [24]3 years ago
3 0

Answer:

hi

Explanation:

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2 years ago
What solute particles are present in an aqueous solution of CH3COCH3?
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Which change does an increase in heat energy cause?
Bumek [7]

Answer:

C more collision between molecules

Explanation:

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5 0
2 years ago
Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
What is chemistry the study of?
IRINA_888 [86]
Chemistry is the study of substances—that is, elements and compounds.
8 0
3 years ago
Read 2 more answers
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