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yKpoI14uk [10]
2 years ago
10

Write your question here (Keep it simple and clear to get the best answer)what are the different types of bleaching agent's

Chemistry
1 answer:
andrew11 [14]2 years ago
6 0
Generally there are two kinds of bleaching agents, notably chlorine (and many chlorine compounds such as sodium hypochlorite) and peroxygen bleaching agents (such as hydrogen peroxide). This isn't to say there aren't others, because there are, such as ammonia. (Note, mixing traditional bleaches and ammonia is very dangerous)
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Which ecosystem is more likely to become unstable one with many kinds of plants and animals or one with few kinds?
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One with a few kinds is more likely to become unstable.

Explanation:

A lack of biodiversity means there is a lower chance of them having traits that enable them to adapt to a changing environment. A lack of biodiversity is usually caused by humans. It could be the result of habitat loss, invasive species, overexploitation, pollution, or climate change.

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What happens when muscle cells are triggered?
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Read 2 more answers
What is the limiting reactant if 0.5 g Al is reacted with 3.5 g CuCl2?
DIA [1.3K]
The balanced equation for the above reaction is 
2Al + 3CuCl₂ --> 2AlCl₃ + 3Cu
stoichiometry of Al to CuCl₂ is 2:3
limiting reactant is when the reactant is fully consumed in the reaction therefore amount of product formed depends on amount of limiting reactant present. 
number of Al moles  - 0.5 g  / 27 g/mol = 0.019 mol
number of CuCl₂ moles - 3.5 g / 134.5 g/mol = 0.026 mol
if Al is the limiting reactant 
if 2 mol of Al reacts with 3 mol of CuCl₂
then 0.019 mol of Al reacts with - 3/2 x 0.019 = 0.029 mol of CuCl₂
but only 0.026 mol of CuCl₂ is present 
therefore CuCl₂ is the limiting reactant 
and 0.026 mol of CuCl₂ reacts with - 0.026/3 x 2 = 0.017 mol of Al is required
but 0.019 mol of Al is present 
therefore CuCl₂ is the limiting reactant and Al is in excess



6 0
3 years ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

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2 years ago
Stock naming please help
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