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sergiy2304 [10]
2 years ago
7

How many grams of helium are equal to 15 moles of methane (CH4)?

Chemistry
1 answer:
Dennis_Churaev [7]2 years ago
5 0

Answer:

0.062334579609362

Explanation:

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In the formate ion, hco2− which of the atoms in the ion have pπ orbitals?
kirza4 [7]
I think it is halico acid

5 0
3 years ago
What are this element’s chemical and physical properties? Explain how the chemical properties affect the physical properties of
Setler79 [48]

Answer:

What element is this. Would you mind inserting a picture or naming the element in the comments section

3 0
3 years ago
2Na2SO4 :How many atoms for each element are in the formula?<br><br> S=<br> O=<br> Na=
yuradex [85]

Answer:

S=  2(1)  = 2

O=  2(4)  = 8

Na= 2(2)  = 4

Explanation:

The given compound is:

          2Na₂SO₄  

An element is a distinct substance that cannot be split up into simpler substances.

So;

  Number of atoms of elements here are:

S=  2(1)  = 2

O=  2(4)  = 8

Na= 2(2)  = 4

6 0
2 years ago
Sodium (chemical symbol Na) is atomic number 11 and is in the first column of the periodic table so it has one valence electron.
lisabon 2012 [21]
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7 0
3 years ago
Read 2 more answers
How many grams of a stock solution that is 92.5 percent H2SO4 by mass would be needed to make 250 grams of a 35.0 percent by mas
IrinaVladis [17]

94.6 g.  You must use 94.6 g of 92.5 % H_2SO_4 to make 250 g of 35.0 % H_2SO_4.

We can use a version of the <em>dilution formula</em>

<em>m</em>_1<em>C</em>_1 = <em>m</em>_2<em>C</em>_2

where

<em>m</em> represents the mass and

<em>C</em> represents the percent concentrations

We can rearrange the formula to get

<em>m</em>_2= <em>m</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>m</em>_1 = 250 g; <em>C</em>_1 = 35.0 %

<em>m</em>_2 = ?; _____<em>C</em>_2 = 92.5 %

∴ <em>m</em>_2 = 250 g × (35.0 %/92.5 %) = 94.6 g

4 0
3 years ago
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