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sergiy2304 [10]
3 years ago
7

How many grams of helium are equal to 15 moles of methane (CH4)?

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

0.062334579609362

Explanation:

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Which of these choices is always a benefit of xeriscaping?
Temka [501]

C. Reduced cost of watering i guess

4 0
3 years ago
There are 43.2 g of carbon to 14.4 g of hydrogen in a sample of methane (CH4). What percent of 37.8 g of methane is carbon?
EastWind [94]

Using the law of constant proportions  which says that within the same compound, elements exist in fixed ratios. 

Therefore; we can use the ratio of total mass to the mass of carbon, to determine the amount of carbon in another sample.

Mass C / Mass CH4 = Mass C / Mass CH4

43.2 g / 57.6 g = Mass C / 37.8 g

Mass C = 37.8 g × 43.2 g / 57.6 g 

              = 28.35 g

Hence; the percentage of carbon will be; 

=(28.35/ 37.8 )× 100%

= 75 % 

Thus; 75% of 37.8 g of methane is carbon

8 0
4 years ago
True or false<br> Volcanoes form along mid ocean ridges where two plates move together
gladu [14]

Answer:

False

Explanation:

5 0
3 years ago
Does methylenecyclohexane obey Zaitsev's rule? why or why not
kifflom [539]

Answer:

Explanation: Zaitsev’s or Saytzev’s (anglicized spelling) rule is an empirical rule used to predict regioselectivity of 1,2-elimination reactions occurring via E1 mechanism or via E2 mechanism. It states that in a regioselective E1 or E2 reaction the major product is the more stable alkene, i.e., the alkene with the more highly substituted double bond.

E1 reaction always follow Zaitsev’s rule; with E2 reactions, there are exceptions (see antiperiplanar).

6 0
3 years ago
.7 liters of CO represents how many molecules?
Ronch [10]

Answer:

               1.88 × 10²² Molecules of CO

Explanation:

At STP for an ideal gas,

Volume = Mole × 22.4 L/mol

Or,

Mole = Volume / 22.4 L/mol

Mole = 0.7 L / 22.4 L/mol

Mole = 0.03125 moles

Now,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 0.03125 × 6.022 × 10²³ Molecules/mol

No. of Molecules = 1.88 × 10²² Molecules of CO

7 0
2 years ago
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