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sergiy2304 [10]
3 years ago
7

How many grams of helium are equal to 15 moles of methane (CH4)?

Chemistry
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

0.062334579609362

Explanation:

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List the names of the elements that make up the molecule?
garik1379 [7]

Answer:i nitrogen, oxygen, hydrogen

Explanation: " Molecules of most elements are made up of only one of atom of that element" well if you search it up

6 0
3 years ago
Read 2 more answers
When elemental boron, B, is burned in oxygen gas, the product is diboron trioxide. If the diboron trioxide is then reacted with
zalisa [80]

<u>Answer:</u> The chemical equation is written below.

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form. This also means that total number of individual atoms on reactant side must be equal to the total number of individual atoms on the product side.  

The chemical equation for the reaction of elemental boron and oxygen gas follows:

4B+3O_2\rightarrow 2B_2O_3

By Stoichiometry of the reaction:

4 moles of elemental boron reacts with 3 moles of oxygen gas to produce 2 moles of diboron trioxide.

The chemical equation for the reaction of diboron trioxide and water follows:

B_2O_3+3H_2O\rightarrow 2H_3BO_3

By Stoichiometry of the reaction:

1 mole of diboron trixoide reacts with 3 moles of water to produce 2 moles of boric acid.

Hence, the chemical equations are written above.

3 0
3 years ago
The smallest unit of a compound is called a ___________.
Oxana [17]
<span>The smallest unit of a compound is called a molecule. The correct option among all the options that are given in the question is the second option or the penultimate option or option "B". The other choices are incorrrect and can be negated. I hope that this is the answer that has actually come to your desired help.</span>
5 0
3 years ago
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
Help me help me help me
PilotLPTM [1.2K]

Answer:

i dont know i do this for points

Explanation:

4 0
2 years ago
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